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Tpy6a [65]
3 years ago
15

Whats the extreme value?y=3(x+5)^(2)-4

Mathematics
1 answer:
natta225 [31]3 years ago
6 0

Answer:

-4

Step-by-step explanation:

  • y = 3(x+5)²-4
  • y= 3(x²+10x+25)-4
  • y= 3x²+30x+75-4
  • y= 3x²+30x+71

Derivate the function

  • y' = 6x+30

solve the equation y'= 0

  • y'= 6x+30
  • 6x+30= 0
  • 6x= -30
  • x = -5

The extrme value of y is reached in -5

y = 3(-5+5)²-4= -4

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8_murik_8 [283]
It’s correct good job
6 0
4 years ago
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Plz help will be marked BRAINLIEST!!<br><br><br> Yed
Natasha2012 [34]

X=−13

Distribute

Subtract

simplify

divide both sides

then simplify again to arrive at your answer.

8 0
3 years ago
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Complete the square to transform the quadratic equation into the form
faltersainse [42]

The square of a binomial is written like

(x\pm a)^2 = x^2\pm 2ax + a^2

In your case, you have 2ax=-8x, which implies a=-4

So, we want to write

(x-4)^2 = x^2-8x+16

But our left hand side is

x^2-8x-10

If we add 26 to both sides, we have

x^2 - 8x - 10 +26 = 18+26 \iff x^2-8x+16=44 \iff (x-4)^2=44

7 0
3 years ago
write an expression that equals (x-13). It must have at leat two sets of parentheses and one minus sogn.Verify that it is equal
IRISSAK [1]

You can perform all kind of operation that are one the inverse of the other, so that the value won't change. For example, you can multiply and divide by 2:

\dfrac{1}{2}(2(x-13))

Or add and subtract 5:

\left(\dfrac{1}{2}(2(x-13))+5\right)-5

4 0
3 years ago
What is the sum of the first 20 terms of the arithmetic sequence shown? \displaystyle \frac{1}{3} 3 1 ​ , \displaystyle \frac{2}
Murrr4er [49]

Answer:

70

Step-by-step explanation:

a_1 = First term = \dfrac{1}{3}

d = Common difference = \dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}

n = Number of terms = 20

Sum of arithmetic progression is given by

S=\dfrac{n}{2}[2a_1+(n-1)d]\\\Rightarrow S=\dfrac{20}{2}\times (2\times \dfrac{1}{3}+(20-1)\dfrac{1}{3})\\\Rightarrow S=70

The sum of the first 20 terms of the arithmetic sequence is 70.

5 0
3 years ago
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