Given:
7 red candies
9 blue candies
12 pink candies
Condition:
Number of bags that has equal number of candies.
We can do 7 bags with 1 colored candy each. There will be an excess of 2 blue candies and 5 pink candies.
We can do 4 bags with 1 red candy, 2 blue candies, 3 pink candies. There will be an excess of 3 red candies and 1 blue candy.
We can do 3 bags with 2 red candies, 3 blue candies, 4 pink candies. There will be an excess of 1 red candy.
7 over 21 . because you add 7 plus 8 plus 6 and get 21 then have 7 white shirts
Given inequality -3(4-6x) < x+5.
We have -3 in front of Parenthesis.
That represents multiplication of -3 and Parenthesis.
The multiplication of Parenthesis could be done by applying distributive property.
On distributing, we get
-12+18x < x+5
x is added on right side of the inequality. The reverse operation of addition is subtraction. So we need to subtract x from both sides, we get
-12+18x-x < x-x+5
-12+17x < 5
Now, we need to get rid -12 from left side.
So, we need to apply addition property of equality, we need to add 12 on both sides, we get
-12+12+18x < x+5+12
17x < 17
We need to get rid 17 from left side. So we need to apply division property of equality.
On dividing both sides by 17, we get
17x/17 < 17/17
x<1.
1.79(4.05 + 2.78) is the answer i had this question and this is the right answer I hope it helps
Answer:
factor left the side of the equation
(2k_9)(k+2)=0
set factors equal to 0
2k_9=0 or k+2=0
the answer is K= 9/2 or K =-2
