Given that the number rolled is odd, it can be 1, 3, or 5 = 3 possibilities.
Only one of the possibilities is success . . . rolling a 3 .
So the probability of success is 1/3 = 33 and 1/3 percent .
B stands for Area of the base in the volume formula
False, since all sides are equal all angles must be equal and when you have an obtuse or right triangle only on angle is obtuse or right. since one is different it cannot be equal on all sides making this statement false
Answer:
I think it is the 3rd one
Step-by-step explanation:
I hope it is. Sorry if not, I tried.
Answer:

Step-by-step explanation:

