Answer:
1 stack of 60
2 stacks of 30
3 stacks of 20
4 stacks of 15
5 stacks of 12
6 stacks of 10
60 stacks of 1
30 stacks of 2
20 stacks of 3
15 stacks of 4
12 stacks of 5
Prime Factorisation
Step-by-step explanation:
To find the number of stacks you can make just divide the total by the size of the stacks. This also works in reverse.
To find the prime factorisation you just find the factors of the number by dividing it by the largest prime possible.
Answer: The question has some details missing and incomplete. here is the complete question ; New regulations in Canada require all Internet service providers (ISPs) to send a notice to subscribers who are downloading files illegally asking them to stop. This "notice and notice" system was already in place with Rogers Cable. That company says that prior to these regulations, 67% of its subscribers who received the notice did NOT reoffend. Consider a random sample of 50 of these Rogers subscribers who received a first notice.
a) What is the distribution (or approximate distribution) of the number X of subscribers who reoffend?
b)Find the mean of the sample proportion of subscribers that REOFFENDED. Report to two decimal places:
c)Find the standard deviation of the sample proportion of subscribers that REOFFENDED. Report to three decimal places:
d)Find the z-score for the 18 of the 50 subscribers who reoffended (report to two decimal places)
e)Find the probability that at least 18 of the 50 subscribers reoffended (report to two decimal places)
Step-by-step explanation:
a) Approximate distribution of the number X of subscribers who reoffend is NORMAL, as both np and n(1-p) are greater than 5.
b) n = 50, 67% of its subscribers who received the notice did NOT reoffend = q, therefore p = 1 - q = 1 - 0.67 = 0.3300, p = 0.3300,
here mean of distribution ; μ = np = 16.5
c) standard deviation σ =√(np(1-p)) = 3.325
d) z score = (X-mean) / SD = (18-16.5) / 3.325=0.45
e) Probability that at least 18 of the 50 subscribers reoffended; P(X>18) = P(Z>0.45) = 0.33
Answer:
S₁₀=620
Step-by-step explanation:
This is an arithmetic sequence with a common difference of d=12
The formula for an arithmetic series is Sₙ=(n/2)(a₁+aₙ) where aₙ is the nth term and a₁ is the first term.
We know that a₁=8 and d=12 where the 10th term would be a₁₀=8+(10-1)12=116.
Therefore, the sum of the first 10 terms of the arithmetic series is S₁₀=(10/2)(8+116)=(5)(124)=620
To start off, the wording of this question is pretty technical. Let's reword the question to make it a bit easier to understand.
From the open interval from -2 to 5 (meaning between but not including those integers), list every integer for x at which x approaches a defined y point on the curve, regardless of whether it actually takes that y value at that point.
Let's start with the first eligible integer, -1.
The limit, from both sides, as x approaches -1 is y=-1.
However, y = -2 at this point.
At 0, x continuous and defined on the curve where you would expect it, and therefore the limit at x=0 is its y value at that point, 0.
x=1 is not eligible, because its left-side limit (when approaching from the left) and right-side limit (when approaching from the right), are distinct.
x=2 has a clear defined limit. It is continuous and defined at that point. The limit looks to be around y= 1.8
x=3 does not feature a clearly defined, finite value, since the limit at x=3 is
-∞
x=4, like x=0 and x=2, has a clear and finite limit, since it is continuous at that point.
Answers are x=-1, x=0, x=2, and x=4
or
{-1, 0, 2, 4}
