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luda_lava [24]
3 years ago
11

From a point on a circle, two perpendicular chords are drawn. One is 6 cm from the center and the other one is 3 cm from the cen

ter. Find the lengths of these chords.
Mathematics
2 answers:
sergeinik [125]3 years ago
8 0
The chord 3cm away is 12cm and chord 6cm away is 6cm. 
The two perpendicular chords will create a rectangle with the center. each side will be half of the parallel sides length.
Ira Lisetskai [31]3 years ago
4 0
The chord 3cm away is 12cm and chord 6cm away is 6cm. 
The two perpendicular chords will create a rectangle with the center. each side will be half of the parallel sides length. 
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15>0.6 (10+n)= that is the full problem
Lemur [1.5K]
N<−1.6 repeating is the answer

the work

Let's solve your inequality step-by-step.
5>0.6(10+n)
Step 1: Simplify both sides of the inequality.
5>0.6n+6
Step 2: Flip the equation.
0.6n+6<5
Step 3: Subtract 6 from both sides.
0.6n+6−6<5−6
0.6n<−1
Step 4: Divide both sides by 0.6.
0.6n
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3 years ago
Solve 6x+c=k for x. <br>btw this wasn't multiple choice.
abruzzese [7]
x=(k-c)/6

6x+c=k
subtract c from both sides
6x=k-c
divide by 6 on both sides
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5 0
3 years ago
A gardener plants a bed of flowers such that he plants twenty day lilies in the first row, twenty-six day lilies in the second r
dlinn [17]
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Farmer Jan is a vegetable farmer who divides his field between broccoli crops and spinach crops. Last year, he grew 6 tons of br
ankoles [38]

Answer:

There is no unique solution to this problem.

There are infinitely many solutions to this problem.

Step-by-step explanation:

Let B denotes broccoli crop

Let S denotes spinach crop

Last year, he grew 6 tons of broccoli per acre and 9 tons of spinach per acre, for a total of 93 tons of vegetables.

Mathematically,

6B + 9S = 93        eq. 1

This year, he grew 2 tons of broccoli per acre and 3 tons of spinach per acre, for a total of 31 tons of vegetables.

Mathematically,

2B + 3S = 31

2B = 31 -  3S

B = (31 -  3S)/2      eq. 2

Substitute eq. 2 into eq. 1

6B + 9S = 93

6[(31 -  3S)/2] + 9S = 93

3(31 -  3S) + 9S = 93

93 - 9S + 9S = 93

- 9S + 9S = 93 - 93

0 = 0

Therefore, there is no unique solution to this problem.

Which means that there are infinitely many solutions to this problem.

5 0
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