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3 years ago

Why does 5(x+20) equal 15x? I'm so confused.

Mathematics

2 answers:

borishaifa [10]3 years ago

7 0

Answer:

Because lma/os

Step-by-step explanation:

5 ( x + 20 )

-----------------

1. Simplifly

2. Distribute

3. 5 ( x + 20 )

5 x + 100

mestny [16]3 years ago

3 0

Answer:

Nobody knows its a mistery :'D

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irga5000 [103]

Answer:

yes, its a heptagon

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

HELP54465745653475vccbxdsztgfghdcdx

vredina [299]

Answer:

Solution is invalid

Step-by-step explanation:

Let the time when they will have the same water content be x hours

At x hours;

For the first tank, the content will be;

50 + 10x

For the second;

29 + 3x

Equating both, will give us x

29 + 3x = 50 + 10x

We will get x as a negative number here

Since number of hours can not be negative, the solution is invalid

4 0

3 years ago

The ordered pair D (-4,-2) has been plotted for you. If you reflected coordinate d over the x-axis, which point from part A woul

Serjik [45]

A= (-4,2)

The x value (-4) stays the same when reflected over the x-axis, so only the y-value gets reflected and therefore changed.
The resultant coordinate is (-4,2)

6 0

3 years ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$