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777dan777 [17]
3 years ago
11

47, 40, 36, 40, 42, 45, 40, 32. Are the mean, median and mode of the above data the same? If not

Mathematics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

mean: 40.25

median: 40

mode: 40

Step-by-step explanation:

No.

If 42 is removed all values will be equal to 40.

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7(2x-5)-11=3(5x-2)-2x
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Answer:

x=40

Step-by-step explanation:

7(2x-5)-11=3(5x-2)-2x      Distribute

14x-35-11=15x-6-2x          Simplify

14x-46=13x-6                   subtract 13x and add 46

x=40

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Triangle AGB is congruent to Triangle CGB.
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3 years ago
28.Neethi had 8
Ludmilka [50]

Answer:

2 1/3 cupcakes

Step-by-step explanation:

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5 0
3 years ago
) Find the coordinates of the point A' which is the symmetric point
soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point  A(3, 2) with respect to the line 2x + y - 12 = 0.​

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

C( \dfrac{x+3}{2}, \dfrac{y+2}{2})

Also, product of slope will be -1 .( Since, they are parallel )

\dfrac{y-2}{x-3} \times -2  = -1\\\\2y - 4 = x - 3\\\\2y - x = 1

x = 2y - 1

So, C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})

Also, C satisfy given line :

2\times ( \dfrac{2y + 2}{2})  + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}

Also,

x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}

Therefore, the symmetric points isA'(\dfrac{31}{5}, \dfrac{18}{5}) .

7 0
3 years ago
Is this happening to anybody else? Why are there ad's to unlock answers it is annoying
kap26 [50]

I don’t have to have ads. When I wasn’t signed up I had to but I logged in and now I don’t have to watch ads.

6 0
3 years ago
Read 2 more answers
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