the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.
The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.
In terms of hyperbola, F1F2=2c, c=20.
The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.
Use formula c^2=a^2+b^2c
2
=a
2
+b
2
to find b:
\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}
(20)
2
=(18)
2
+b
2
,
b
2
=400−324=76
.
The branches of hyperbola go in y-direction, so the equation of hyperbola is
\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1
b
2
y
2
−
a
2
x
2
=1 .
Substitute a and b:
\dfrac{y^2}{76}- \dfrac{x^2}{324}=1
76
y
2
−
324
x
2
=1 .
I believe the correct answer is 914 yd ^3hope this helps!
The Answer: (-b + 15) (15 - b)
Answer:
Triangle P and Triangle Q are mathematically similar shapes (?).
Step-by-step explanation:
Hi, so the question asks which statement is true, given the following information, but you haven't written what statements we can choose from.
After reading the information, we can see that Triangle Q is the same shape as Triangle P but just larger.
I'm assuming that one of the statements given is about Triangle P and Triangle Q being mathematically similar shapes?
If you need to show your working out, here it is:
18 ÷ 6 = 3
24 ÷ 8 = 3
30 ÷ 10 = 3
All the angles are the same.
This means that the length scale factor is +3 from Triangle P to Triangle Q, the area scale factor is +9 (because 3 x 3 = 9) from Triangle P to Triangle Q, and that the two shapes are mathematically similar.
*DISCLAIMER* The majority of question askers on Brainly seem to be from the US, and I'm not, so the way I work things out / the mathematical terms I use might be different. Sorry!
Hope this helped anyway!
Bluey :)
