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3 years ago

What is the equation of the line that has a slope of -4 and goes through (-1,6) ?

Mathematics

1 answer:

Feliz [49]3 years ago

5 0

Answer:

The answer to this is: C

$y - 6 = -4(x +1)$

Step-by-step explanation:

Using the formula:

$y-y_1=m(x-x_1)$

and inserting what we are given:

m = - 4

(m is the symbol which represents slope)

(-1, 6)

This point coordinate represents our:

$x_1 = -1$

$y_! = 6$

When inserted into our formula (point slope form formula)

It will look like this:

$y - (6) = -4(x - (-1))$

Then solve it from there!

(There is a double negative, which will make it positive)

Giving you:

$y - 6 = -4(x +1)$

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Lorico [155]

Answer:

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Step-by-step explanation:

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AVprozaik [17]

Answer: (x - 1)(x + 1)^2(x - 4)^3

Step-by-step explanation:

First, remember that:

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Then we have the expression:

(x-b)(x-c)^2(x-d)^3

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3 years ago

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Answer:

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$x=-x+360^{\circ \:}n+110^{\circ \:}$ (Add x to both sides)

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zalisa [80]

Answer:

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4 years ago