Question

What is the equation of the line that has a slope of -4 and goes through (-1,6) ?

Answer 1

Answer:

The answer to this is: C

$y - 6 = -4(x +1)$

Step-by-step explanation:

Using the formula:

$y-y_1=m(x-x_1)$

and inserting what we are given:

m  = - 4

(m is the symbol which represents slope)

(-1, 6)

This point coordinate represents our:

$x_1 = -1$

$y_! = 6$

When inserted into our formula (point slope form formula)

It will look like this:

$y - (6) = -4(x - (-1))$

Then solve it from there!

(There is a double negative, which will make it positive)

Giving you:

$y - 6 = -4(x +1)$