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77julia77 [94]
3 years ago
11

What is the value of the point on the number on the number line?

Mathematics
1 answer:
Ratling [72]3 years ago
5 0

Answer:

4/6

mark me brainliest please

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What is the surface area and what do I need to do?
kari74 [83]

check the picture below, that's pretty much the same block, or "rectangular prism", with a width of 10, length of 5 and height of 1.


so anyhow, is really 6 rectangles stacked up to each other at the edges, so, we can simply get the area of each of those rectangles, add them up and that's the surface area.


front and back, two rectangles of  5x1

left and right, two rectangles of 1x10

top and bottom, two rectangles of 10x5


\bf \stackrel{\textit{front and back}}{2(5\cdot 1)}+\stackrel{\textit{left and right}}{2(1\cdot 10)}+\stackrel{\textit{top and bottom}}{2(10\cdot 5)}

5 0
3 years ago
What's the additive identity of 9
Zigmanuir [339]
9? Thats what it is,
5 0
3 years ago
ILL GIVE BRAINLIEST ON THIS QUESTION!!!!!!!!!!!!!!!!!!!!!!!!!!!
DochEvi [55]

Answer:

15.25 or 15 if you need it to be rounded.

Step-by-step explanation:

-11 on both sides to get 5x=1x+61. Then, -1x on both sides to get 4x=61. Then to find x you do 61 divided by 4 which is 15.25.

8 0
3 years ago
Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0
1 year ago
Order these numbers from least to greatest. −14.2 , −14313 , 14110 , −202
Firlakuza [10]
-14313,-202,-14.2,14110
4 0
3 years ago
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