Question in the image
1 answer:
You might be interested in
The square root and cube root identities are proved.
According to the statement
we have to find that the use of the square root identity (x − y)2 = x2 − 2xy + y2
And use of cube root identity a3 + b3 = (a + b)(a2 − ab + b2).
So, For this purpose, we know that the
A. Let us assume the two conditions.
So,
2x + 3y = 6 -(1)
4x + 7y = 8 -(2)
Here we use elimination method
So, Multiply 4 with (1) and 2 with (2)
8x + 12y = 24
8x + 14y = 16
Now eliminate x from these equations
-2y = 8
here y is -4.
and the x become
2x + 3y = 6
2x -12 = 6
2x = 18
x = 9.
B. For the use of identity
Let us assume a number 26 and 28 then fill it in the condition then
Then
And we have to prove the cube root identity then
The identity is
Then let us assume the number 8 and 9 then
Hence by this way we prove the square and cube root identities.
So, The square root and cube root identities are proved.
Learn more about square root and cube root here
#SPJ1