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BaLLatris [955]
3 years ago
6

At a basketball​ game, a team made 58 successful shots. They were a combination of​ 1- and​ 2-point shots. The team scored 99 po

ints in all. Write and solve a system of equations to find the number of each type of shot.
Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Step-by-step explanation:

Step-by-step explanation:

1.Right

2.Left

3.Bottom Middle

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asambeis [7]
You can ask and answer questions
4 0
3 years ago
Read 2 more answers
The factors of 55 are________________________________.I know that 55 is a (prime/composite) number because...
statuscvo [17]

Answer:

11 & 5 are the factors of 55

Step-by-step explanation:

Factors of 55

11 × 5 = 55

Thus, 11 & 5 are the factors of 55

 

<u>-TheUnknownScientist</u><u> 72</u>

7 0
3 years ago
Choose the solutions to the quadratic equation x2 – 8x – 9 = 0. –21 –1 9 29
8090 [49]

Answer:

-1 and 9

Step-by-step explanation:

To solve the quadratic, factor and set its factors equal to 0. Factoring is the action of breaking up a polynomial into pieces which multiply to make it. The factors are found by multiplying numbers to make C and add to B of ax^2+bx+c.

Here c = -9 and b = -8. The numbers -9 and 1 multiply to -9 and add to -8. These are the factors (x-9)(x+1).

Set each equal to 0 and solve for x.

x-9 = 0

x = 9

x+1 =0

x = -1

6 0
3 years ago
Help me with my math for brainiest:)
MissTica
Answers:
1. P=3

Step by step:
P-5=-2 -move the constant to the right hand side and change its sign

P=-2+5 - calculate the sum

P=3


2. W=-2.8

Step by step:
W+13.2=10.4 - move the constant tot he right hand side and change its sign

W=10.4-13.3 - calculate the difference

W=-2.8

3. X=2/3

Step by step:
X-5/6=-1/6 - move the constant to the rig hand side and change its sign

X=-1/6+5/6 - calculate the sum

X=2/3


7 0
3 years ago
The general form of a circle is given as x^2+y^2+4x - 12y + 4 = 0. A) What are the coordinates of the center of the circle? B) W
Alex_Xolod [135]

Answer:

center = (-2, 6)

radius = 6

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

(where (a, b) is the center and r is the radius)

Therefore, we need to rewrite the given equation into the standard form of an equation of a circle.

Given equation:

x^2+y^2+4x-12y+4=0

Collect like terms and subtract 4 from both sides:

\implies x^2+4x+y^2-12y=-4

Complete the square for both variables by adding the square of half of the coefficient of x and y to both sides:

\implies x^2+4x+\left(\dfrac{4}{2}\right)^2+y^2-12y+\left(\dfrac{-12}{2}\right)^2=-4+\left(\dfrac{4}{2}\right)^2+\left(\dfrac{-12}{2}\right)^2

\implies x^2+4x+4+y^2-12y+36=-4+4+36

Factor both variables:

\implies (x+2)^2+(y-6)^2=36

Therefore:

  • center = (-2, 6)
  • radius = √36 = 6
7 0
2 years ago
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