If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l
now
solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum
notice the
so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0
so.. check the critical points on the other
Download math papa.... helped me tremendously
total units of ration = 4 +7=11
so, ratio would be (4*33)/11 : (7*33)/11
12 : 21 is the answer.
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Answer:
Port r is 100° from Port p and 26km from Port p
Step-by-step explanation:
Lets note the dimension.
From p to q = 15 km = a
From q to r = 20 km= b
Angle at q = 50° + 45°
Angle at q = 95°
Ley the unknown distance be x
Distance from p to r is the unknown.
The formula to be applied is
X²= a²+ b² - 2abcosx
X²= 15² + 20² - 2(15)(20)cos95
X²= 225+400-(-52.29)
X²= 677.29
X= 26.02
X is approximately 26 km
To know it's direction from p
20/sin p = 26/sin 95
Sin p= 20/26 * sin 95
Sin p = 0.7663
P= 50°
So port r is (50+50)° from Port p
And 26 km far from p
Answer:
<em>well non of the answer choices are exact but i would say a/the first one. im not sure but they should add up to about 7.65%.</em>
Step-by-step explanation:
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