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zysi [14]
3 years ago
10

Evaluate the line integral

Mathematics
1 answer:
Lorico [155]3 years ago
3 0

It looks like you're asked to compute

\displaystyle\int_C y\,\mathrm dx + z\,\mathrm dy + x\,\mathrm dz

where <em>C</em> is parameterized by ⟨<em>t</em>, <em>t</em>, <em>t</em>⟩ with 0 ≤ <em>t</em> ≤ 1.

In other words, <em>x</em> = <em>y</em> = <em>z</em> = <em>t</em>, so d<em>x</em> = d<em>y</em> = d<em>z</em> = d<em>t</em>, and the integral reduces to

\displaystyle\int_C y\,\mathrm dx + z\,\mathrm dy + x\,\mathrm dz = \int_0^1 t\,\mathrm dt + t\,\mathrm dt + t\,\mathrm dt \\\\ = 3 \int_0^1 t\,\mathrm dt \\\\ =\frac32t^2\bigg|_{t=0}^{t=1} \\\\ =\boxed{\frac32}

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san4es73 [151]

Answer:

30°

Step-by-step explanation:

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∠C = 2 * ∠B

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<A + (∠A + 20) + (2 * (∠A + 20)) = 180

<A + (∠A + 20) + 2∠A + 40 = 180

4∠A + 60 = 180

4∠A = 120

∠A = 30

5 0
4 years ago
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AysviL [449]

Answer:

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Step-by-step explanation:

Given the equation

y=-\frac{2}{5}x-1

comparing the equation with the slope-intercept formy=mx+b

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so the slope of the line is m = -2/5

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line,

so  the slope of the perpendicular line will be: 5/2

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y+8=\frac{5}{2}\left(x-2\right)

subtract 8 from both sides

y+8-8=\frac{5}{2}\left(x-2\right)-8

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8 0
3 years ago
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Like you would multiply x² by x, 8x by x, -3 by x (thats the first row)

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Then you get those final variables and combine like terms getting the answer above

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3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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