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Effectus [21]
3 years ago
10

If x=1+√2 find the value of(x+1/x)^3

Mathematics
1 answer:
Musya8 [376]3 years ago
6 0
Answer will be 1 or 20+14 root 2/1+11 root 2
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I need help with this problem
zloy xaker [14]
2.3 x 10^-3 * 4.2 x 10^2 =
.0023 * 420 =
<span> <span> <span> 0.966 </span> </span> </span>




3 0
2 years ago
Read 2 more answers
HURRY PLEASEEE PLEASE PLEASE!!!!!!!!!
Likurg_2 [28]

Answer: 2000 tickets were sold

Step-by-step explanation:

8000 divided by 40 percent is 200

6 0
3 years ago
Read 2 more answers
Find the midpoint of A and B where A has coordinates (-5, 3)<br> and B has coordinates (3,-1)
yaroslaw [1]

Answer:

(-1, 1)

Step-by-step explanation:

Midpoint formula: (x₁ + x₂/2 , y₁ + y₂/2)

Substitute the values into the formula.

(-5 + 3/2 , 3 - 1/2)

(-2/2 , 2/2)

(-1,1)

Therefore, the midpoint is (-1, 1).

5 0
3 years ago
Pleaseee helpppp mehhhh
Tanya [424]

Answer:

-13x^2 + 6x + 11

Step-by-step explanation:

Just subtract the numbers that are similar (i.e. -5x^2 - 8x^2)

6 0
2 years ago
FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{20} = \frac{20}{2} [ (2 × - 1) + (19 × 4) ]

     = 10(- 2 + 76) = 10 × 74 = 740

8 0
3 years ago
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