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Ilya [14]
2 years ago
8

Every round in a competition costs 30 diamonds and you get 10 shards. How many diamonds will it cost you to reach 1,024 shards?

Mathematics
1 answer:
Firdavs [7]2 years ago
3 0

Answer:

3,090 diamonds

Step-by-step explanation:

To get 10 shards, you need to spend 30 diamonds.

First thing we need to find, how many rounds you need to play to get 1,024 shards if in each round you win 10 shards?

1,024/10 = 102,4

But you can not play 102.4 rounds, you only can play whole numbers, so we need to round it to the next whole number (not the previous one, because in that case, we would get less than 1,024 shards)

Then you need to play 103 rounds.

And each round costs 30 diamonds, then the total number of diamonds that you need is:

103*30 diamonds = 3,090 diamonds

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Sauron [17]
(-\frac{1}{3})(x+6)=0\\\\\frac{1}{3}(x+6)*3=0*3\\\\-1(x+6)=0\\\\-(x+6)*-1=0*-1\\\\x+6=0\\\\x=-6
3 0
3 years ago
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226.19 divided by 2/3
Tanzania [10]
226.19 / 2/3 =
226.19 x 3/2 =
226.19 x 1.5 =
339.285

339.285 is your answer.
5 0
3 years ago
I GIVE BRAINLIEST PLS HELP
ioda
The answer is 8
Here's why:
{ ( \frac{( {6}^{7}) \times ( {3}^{3})  }{(  {6}^{6}) \times ( {3}^{4}  ) } )}^{3}  =   \\ ( \frac{6}{3} ) ^{3}  =  \\ \frac{216}{27}  = 8
The exponents are subtracted one from another when divided.
\frac{ a ^{b} }{ {a}^{c} } =  {a}^{b - c}
We can look at the problem this way:
( \frac{6^{7} }{6 ^{6} }  \times  \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6}  \times  {3}^{3 - 4} ) =  \\ ({6}^{1}  \times  {3}^{ - 1} )
Since we have the power of -1 on the 3, we apply this rule:
{a}^{ - b}  =  \frac{1}{ {a}^{b} }
Also this rule because we have the power of 1 on the 6:
{a}^{1}  = a
Then we get this:
(6 \times  \frac{1}{3} )^{3}  = ( \frac{6}{3} )^{3}
We apply the rule:
( \frac{a}{b}) ^{c}   =  \frac{ {a}^{c} }{ {b}^{c} }
We get this:
\frac{{6}^{3} }{ {3}^{3} } =  \frac{216}{27}  = 8
4 0
3 years ago
A company purchased $10,000 of merchandise on January 5 with terms 2/10, n/30. On January 7, it returned $1,200 worth of merchan
s2008m [1.1K]

Answer:

C. Debit Accounts Payable $8,800; credit Merchandise Inventory, $176; credit Cash $8,624.

Step-by-step explanation:

Data given in the question is inconsistent with the options given.

Terms 2/10, n/30 means there is a discount of 2% is available on payment of due amount within discount period of 10 days after sale with net credit period of 30 days.

Purchases = $10,000

Returns = $1,200

Amount Due = $10,000 - $1,200 = $8,800

As the payment is made after discount period, so no discount will be availed. Full amount of $8,800 will be paid.

A similar and correct question is given below and answer is made accordingly.

A company purchased $10,000 of merchandise on January 5 with terms 2/10, n/30. On January 7, it returned $1,200 worth of merchandise. On January 12, it paid the full amount due. Assuming the company uses a perpetual inventory system, and records purchases using the gross method, the correct journal entry to record the payment on January 12 is:

Debit Accounts Payable $10,000; credit Merchandise Inventory $200; credit Cash $9,800.

Debit Merchandise Inventory $8,800; credit Cash $8,800.

Debit Accounts Payable $8,800; credit Merchandise Inventory, $176; credit Cash $8,624.

Debit Cash $1,600; credit Accounts Payable $1,600.

Debit Accounts Payable $8,624; credit Cash $8,624.

Solution

Terms 2/10, n/30 means there is a discount of 2% is available on payment of due amount within discount period of 10 days after sale with net credit period of 30 days.

Purchases = $10,000

Returns = $1,200

Amount Due = $10,000 - $1,200 = $8,800

As the payment is made within discount period, so discount will be availed

Discount = $8,800 x 2% = $176

Cash Paid = $8,800 - $176 = $8,624

5 0
3 years ago
A store advertises 15% off an item that regularly sells for $300.
Ilia_Sergeevich [38]

Regular price = 300

Sale = 15%

Price after sale

= 300 - 15%(300)

= 300 - 15/100 x 300

= 300 - 15 x 3

= 300 - 45

= 255

7 0
3 years ago
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