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Dimas [21]
3 years ago
6

Find the percent of the area under the density curve where x is more than 3. ​

Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer:

The percent of the area under the density curve where x is more that 3 is 25 %.

Step-by-step explanation:

Since the density curve is a linear function, the area under the curve can be calculated by the geometric formula for a triangle, defined by the following expression:

A = \frac{1}{2}\cdot (x_{f} - x_{o})\cdot  (y_{f}-y_{o}) (1)

Where:

A - Area, in square units.

x_{f} - x_{o} - Base of the triangle, in units.

y_{f} - y_{o} - Height of the triangle, in units.

The percent of the area is the ratio of triangle areas under the density curve multiplied by 100 per cent, that is:

x = \frac{\frac{1}{2}\cdot (5-3)\cdot (0.25) }{\frac{1}{2}\cdot (5-1)\cdot (0.5) }\times 100\,\%

x = 25\,\%

The percent of the area under the density curve where x is more that 3 is 25 %.

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Answer: The Given sequence is 9, 10, 11, 12

We need to find the expression to describe the sequence.

Let  be the  term of the sequence.

Let n represent the position of the term.

Let a be the first term in the sequence.

and d be the common difference between the sequence

Hence the expression to find the above sequence is given below;

when n=1 d= 1 a = 9

when n=2 d= 1 a = 9

when n=3 d= 1 a = 9

when n=3 d= 1 a = 9

Hence the expression is

Step-by-step explanation:

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3 years ago
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Naya [18.7K]

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Step-by-step explanation:

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3 years ago
2x=14<br>Find the value of x.​
Rashid [163]

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2x=14

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6 0
3 years ago
Read 2 more answers
Which decimal is equivalent to 2.5%​
Vesna [10]

Answer:

0.025

Explanation:

Divide the percentage by 100 to convert it to decmals.

for example 20%=

20

100

=.2

30%=

30

100

=

.3

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2.5

100

=

.025

8 0
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Question in picture<br><br>A) 16/63<br><br>B)-16/63<br><br>C) 63/16<br><br>D) -63/16
Orlov [11]
ANSWER
\tan(x + y) =  -  \frac{63}{16}


EXPLANATION


We were given that,

\csc(x)  =  \frac{5}{3}

This implies that,

\sin(x)  =  \frac{3}{5}

We use the Pythagorean identity

\sin^{2} (x)  +  \cos^{2} (x)= 1
to get,


\cos(x)  =  \sqrt{1 - ( { \frac{3}{5} })^{2}}  =  \frac{4}{5}


We were also given that,


\cos(y)  =  \frac{5}{13}

This means that,


\sin(y)  =  \sqrt{1 -  {( \frac{5}{13}) }^{2} }  =  \frac{12}{13}

This is because,


0 <  \: x \:  <  \frac{\pi}{2}


0 <  \: y \:  <  \frac{\pi}{2}

This angles are in the first quadrant so we pick the positive values.

\tan(x + y)  =  \frac{ \sin(x + y) }{ \cos(x + y) }


\tan(x + y)  =  \frac{ \sin(x ) \cos(y)   +  \sin(y)  \cos(x) }{ \cos(x) \cos(y)  -  \sin(x)  \sin(y) }



\tan(x + y)  =  \frac{  \frac{3}{5}   \times  \frac{5}{13}  +   \frac{12}{13}   \times  \frac{4}{5}  }{  \frac{4}{5}  \times  \frac{5}{13}   -   \frac{3}{5}  \times  \frac{12}{13}  }



\tan(x + y) =  -  \frac{63}{16}

The correct answer is D
4 0
3 years ago
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