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madreJ [45]
3 years ago
13

For every 10,000 gallons of pool water, there needs to be 1 gallon of liquid chlorine. Steve has a 55,000 gallon pool. How much

liquid chlorine does he need to add to his pool?​
Mathematics
1 answer:
Rudik [331]3 years ago
6 0

Answer:

5.5 Gallons

Step-by-step explanation:

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Suppose you are driving to visit a friend in another state. you are driving 55 miles per hour. you must drive 440 miles total. i
Oliga [24]
Time=(distance)/(speed)
speed=55 mi/hr
Total distance=440 miles
Distance covered=275 miles
remaining distance=440-275=165 miles
Time taken to cover the remaining distance will be:
time=165/55=3 hours

Total time taken to travel=440/55=8 hours
if we are to use the equation given by:
55h+275=440
time taken will be found by solving for h, thus we shall have:
55h=440-275
55h=165
h=165/55
h=3 hours

Answer: 3 hours

7 0
3 years ago
Find the side length x. Round your answer to the nearest hundredth.
Alchen [17]
Side length-80

So we know that for a Right Angle, both sides have to measure up to 90 degrees. If one side is 10, and both sides need to add up to 90, then we can take 10 away from 90. That would be 80. 80 + 10 = 90. So the missing side length is 80.


-DustinBR
3 0
3 years ago
You saved $300 to spend over the summer part c
juin [17]

Answer:

huh?

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If A and B are two points having coordinates (- 2, 2) and (2,-4) respectively, find the coordinates of P such that AP= AB.​
Karo-lina-s [1.5K]

Answer:

(0,1)

Step-by-step explanation:

The mid point of A(-2,2) and B(2,-4) is the coordinates of point P, which is (x,y)

Hence, the line AB = AP + PB.

At point AP: x = (-2+2)/2 = 0

also, point PB: y = (2 - 4)/2 = -1

Therefore, coordinates of point P = (0,-1)

7 0
3 years ago
Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i
lana66690 [7]

In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2

which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

which is a circle centered at (0, -10, 3) of radius \sqrt{21}.

3 0
3 years ago
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