Help here pls. im just confused on what its asking me

A small business earns a profit of $6500 in January and $17,500 in May. What is the rate of change in profit for this time perio

MAXImum [283]

Rate of change of profit for this period is $2750 per month

Solution:

Given that,

Profit of $6500 in January and $17,500 in May

To find: Rate of change

Since,

January is the first month of the year (1) while May is the fifth month (5)

Therefore, we get two points

(1, 6500) and (5, 17500)

Using these points we can find the rate of change in profit for this time period

The rate of change using the following formula:

$m = \frac{y_2-y_1}{x_2-x_1}$

Here from the points,

$(x_1, y_1) = (1, 6500)\\\\(x_2, y_2) = (5, 17500)$

Therefore, rate of change is given as:

$m = \frac{17500-6500}{5-1}\\\\m = \frac{11000}{4}\\\\m = 2750$

Thus rate of change of profit for this period = $2750 per month

8 0

3 years ago

Eber ran 3 miles. He stopped to take a break every 34 mile. How many times did Eber stop, including his final stop at the end of

Elodia [21]

144 because when you divide them and simplify

3 0

2 years ago

Pls hurry i am on a timed test

prohojiy [21]

Answer:

4th option

Step-by-step explanation:

Each interval is 2 units. Because in between the two points there are 21 intervals, the range is 42 (21*2).

8 0

3 years ago

Find the slope of the line through the given points (-7, 7), (-1,10)

IgorLugansk [536]

Answer:

The slope would be 1/2.

Step-by-step explanation:

When solving questions like these, make sure to plug in the points into the formula: $\frac{y_{2} - y_{1}}{x_{2} - x_{1}} = slope$ . y2 would stand for the y coordinate of the second point, y1 would stand for the y coordinate of the first point. While x2 would stand for the x coordinate of the second point and x1 for the x coordinate of the first point. Once plugged in, it should look like this: $\frac{10-7}{-1-(-7)}$ . That should then give you the slope of 1/2. Hope this helps!! :D

6 0

2 years ago

write an equation for an ellipse centered at the origin, which has foci at (+-3,0) and co vertices at (0+-4)

natali 33 [55]

Answer:

The equation for an ellipse centered at the origin with foci at (-3, 0) and (+3, 0) and co-vertices at (0, -4) and (0, +4) is:

$\frac{x^{2}}{7} + \frac{y_{2}}{16} = 1$

Step-by-step explanation:

An ellipse center at origin is modelled after the following expression:

$\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$

Where:

$a$ , $b$ - Major and minor semi-axes, dimensionless.

The location of the two co-vertices are (0, - 4) and (0, + 4). The distance of the major semi-axis is found by means of the Pythagorean Theorem:

$2\cdot b = \sqrt{(0-0)^{2}+ [4 - (-4)]^{2}}$

$2\cdot b = \pm 8$

$b = \pm 4$

The length of the major semi-axes can be calculated by knowing the distance between center and any focus (c) and the major semi-axis. First, the distance between center and any focus is determined by means of the Pythagorean Theorem:

$2\cdot c = \sqrt{[3 - (-3)]^{2}+ (0-0)^{2}}$