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Nikitich [7]
3 years ago
13

The image below shows the download speed of three different companies. Use the information to answer the questions.

Mathematics
1 answer:
inessss [21]3 years ago
5 0

Answer:

1) The download speed for AT&T is 1,800

2) The download speed for Bidmore is 1,500

3) The download speed for Comcast is 1,680

4) AT&T has the best download speed out of the three.

5) They will go through the origin and be a proportional line.

Step-by-step explanation:

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Assume you are in a city that is arranged in square blocks, like a coordinate plane, and you are looking at a map. Explain how t
s344n2d4d5 [400]
Go south(down) 4 blocks and west(left) 3 blocks!
4 0
3 years ago
The figure for the other questions
stira [4]
I can't really measure the angles. I can tell you what they look like they'd be. There are three reasons why not. 
1. The paper is slightly bulged where your hand is
2. The circle is slightly distorted by the camera. This  is not that critical. 
3. It is very hard to measure on a computer screen.
There is nothing you could do to make it any better. In fact, given what you had to do, this is a pretty good representation. 

The Three angles -- Question 22
Using the crudest tools you could imagine, I measured the angle where you have written two 90s between the arms as 132°. That angle opens towards the bottom of the page.

The angle that you have called 95 degrees is actually pretty close. I think you read the upper set of numbers on the protractor when you should have been reading the lower set. I make it 89, but I'll bet it is intended to be 90 degrees. 

The third angle on your right is the same as the first one. It comes in at about 132° using my tools again. 

Question 23
I can help you with this. When you are asked to make an equation, you have to use an equal sign somewhere. 

The sum of the three angles should be 360° I'm going to create an error term because I'm almost sure what I measured won't make 360. All circles when you make angles from any point inside them should make angles that add up to 360° when measured with a protractor if the rays of the angles all start from the same point. [If you don't know what a ray is, call it "the arms of the angles"].

So let's create the equation.
Angle1 + angle2 + angle3 + E = 360°
Angle1 = 89° 
Angle2 = 132°
Angle3 = 132°
E is the error that represents the amount away from 360. Your teacher doesn't expect you to get this or to set it into your equation. The main thing you were supposed to do is add up the angles as you tried to do and state what your total was. This is what was expected.
Total = angle1 + angle2 + angle3
Total = 89 + 132 + 132 = 353. My error is 7° too little. So in my equation E = 7°

What to do
Somebody had to mark this with that green felt. You have a teacher. Go to the teacher and ask to be shown how to read the protractor if that person knows. You just need a bit of help. If the teacher cannot tell you, go to someone in your class who knows about that sort of thing and ask them. You're pretty close to getting it.

6 0
3 years ago
G ^-1(3)=<br><br><br> A.-1<br> B.0<br> C.3<br> D. 5<br><br> Please help me understand this!!
Natasha2012 [34]
The answer the 3,

First you have to apply the exponent rule which is 1 - 3• 1/g

Then you multiply the fractions - 1•3/g

Then multiply the numbers 1 and 3, which is 3, so there you have it 3/g, or 3, they’re the same thing.
8 0
2 years ago
1
Blizzard [7]
I believe it is false.
7 0
3 years ago
Read 2 more answers
When a bactericide is added to a nutrient broth in which bacteria are​ growing, the bacteria population continues to grow for a​
baherus [9]

Answer:

a)  1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t​ is given by:

b(t) = 9^6 + 6^4t-6^3t^2

We differentiate the given function.

Thus, the growth rate is given by:

\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t

a) Growth rates at t = 0 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}

b) Growth rates at t = 3 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}

c) Growth rates at t = 6 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=6}= 6^4-2(6^3)(6) = -1296\text{ bacteria per hour}

3 0
3 years ago
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