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ira [324]
3 years ago
5

Somebody please help me :(

Mathematics
1 answer:
katen-ka-za [31]3 years ago
6 0
A, C, and E are the correct answers
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Parcc chapter 7 pythagorean theorem
Bumek [7]
So, we know that a^2 + b^2 = c^2.  Right?  That is called the Pythagorean Theorem.

In this case.  We can say that 39 is a, 40 is b, and x is c.
NOTE: It doesn't really matter whether 39 is a or b.  a & b are just the two legs of the right triangle.

So, if we say that 39 is a, 40 is b, and x is c.  We can plug it into the Pythagorean Theorem.

39^2 + 40^2 = x^2

I'll let you take it from there.



7 0
3 years ago
-8p^4+12p^3+4p^4-8p^2+3p^2
Umnica [9.8K]

Answer:

-8p^4+12p^3+4p^4-8p^2+3p^2

=-8p^4+4p^4+12p^3-8p^2+3p^2

=-4p^4+12p^3-5p^2

=p^2(-4p^2+12p-5)

note: If you have to solve for X

there are steps according to formula

3 0
2 years ago
7 POINTS!!! EASY!!BUT I AM SMALL. A skateboarder traveled 3 5 of a mile in 1 20 of an hour. What was the skateboarder’s speed in
Alex17521 [72]
Speed = distance ÷ time so it's probably
35÷120=0.291 or 7/24 miles per hour
7 0
3 years ago
Read 2 more answers
Find the VOLUME of this composite solid.
Black_prince [1.1K]

Answer:

  (294π +448) cm³ ≈ 1371.6 cm³

Step-by-step explanation:

The half-cylinder at the right end has a radius of 7 cm, as does the one on top. Together, the total length of these half-cylinders is 8 cm + 4cm = 12 cm. That is equivalent in volume to a whole cylinder of radius 7 cm that is 6 cm long.

The cylinder volume is ...

  V = πr²h = π(7 cm)²(6 cm) = 294π cm³

__

The cuboid underlying the top half-cylinder has dimensions 4 cm by 8 cm by 14 cm (twice the radius). So, its volume is ...

  V = LWH = (4 cm)(8 cm)(14 cm) = 448 cm³

Then the total volume of the composite figure is ...

  (294π +448) cm³ ≈ 1371.6 cm³

8 0
3 years ago
Question 13 (Essay Worth 8 points)
mixer [17]

9514 1404 393

Answer:

  geometric sequence

Step-by-step explanation:

The terms of the sequence have a common ratio of -12/3 = -4, so the sequence is geometric. The general term is ...

  an = 3(-4)^(n-1)

so the sum can be written as ...

  \displaystyle\sum_{n=0}^\infty3(-4)^n

(Note the summation starts at n=0, corresponding to a first term of 3.)

3 0
3 years ago
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