Answer:
foreign stamps = 299
US stamps = 353
Step-by-step explanation:
Let number of foreign stamps be x.
Given she has 54 more U.S stamps than foreign , US stamps = x +54
Total stamps = US + Foreign
652 = x + 54 + x
652 - 54 = 2x
598 = 2x
x = 299
Answer:
i)The correct option is D.) 99.74%
ii) The correct option is B.) 68.26%
Step-by-step explanation:
i) P(10≤X≤70) = P( (10−40)/10 ≤Z≤ (70−40
)/10 ) = Pr(−3≤Z≤3)
= 0.9987 - 0.0013 = 0.99734
Therefore the percentage of Jen's monthly phone bills are between $40 and $100 is D.) 99.74%
ii)P(2.1≤X≤3.1) = P( (2.1 − 2.6) /0.5 ≤ Z ≤ (3.1−2.6
)/0.5) = Pr(−1 ≤Z ≤1)
)
= 0.8413 − 0.1587 = 0.6826
Therefore the percentage of students at college have a GPA between 2.1 a,d 3.1 is B.) 68.26%
Marilyn's net pay will increase by $18.15 as her Federal Withholding Allowance increases from 3 to 4.
<h3>What is Federal Withholding Allowance?</h3>
A Federal Withholding Allowance is an exemption that lowers the amount of income tax you must deduct from an employee's paycheck.
Given: The following are the deductible computation:
- For federal withholding allowance = 3:
- Social Security Tax: 6.2% of $810 =
= $50.22 - Medicare tax : 1.45% of $810 =
= $11.745 - State tax: (21% of 3)% of $810=
= 0.63% of $810 = 
= $5.103
Total = $67.068; deducted amount of his gross pay = $810 - $67.068 $742.932 (3 federal withholding).
- For Federal Withholding Allowance = 4:
- State tax: (21% of 4)% of $810 =
= 0.84% of $810 = 
= $6.8704
Thus, as we can see from the calculations, the State taxes increased from $5.103 to $6.8704. Hence, the net pay increases by $18.15 as the federal allowance increases from 3 to 4.
To learn more about Federal Withholding Allowance, refer to the link: brainly.com/question/1212566
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Answer:
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Step-by-step explanation:
Here n= 20
Sample mean GPA = x`= 2.84
Standard mean GPA = u= 2.55
Standard deviation = s= 0.45.
Level of Significance.= ∝ = 0.01
The hypothesis are formulated as
H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students
against the claim
Ha: u1≠u2
i.e the GPA of night students is different from the mea GPA of day students
For two tailed test the critical value is z ≥ z∝/2= ± 2.58
The test statistic
Z= x`-u/s/√n
z= 2.84-2.55/0.45/√20
z= 0.1441
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
