Answer:
The answer of the addition of 3/5, 5/8 and 15/32 is 1/2
Step-by-step explanation:
3/5 + 5/8 + 15/32
We find the LCm of the denominators, that is, 5, 8 and 32
LCM = 5*32 = 160
[(160/5 + 3) + (160/8 + 5) + (160/32 + 15)]/160
[(32+3) + (20+5) + (5+15)]/160
[35+25+20]/160
80/160 = 1/2
I have attached a screenshot with the complete question
Part (1):We are given the prototype used for building the wall with the following dimensions:
long side = 8 in
short side = 5 in
Now, in the wall itself, we want to find the value of the length "a".
This length represents the short side in the prototype used in building the wall.
Therefore:
a = 5 in
Part (2):We are given the prototype used for building the wall with the following dimensions:
long side = 8 in
short side = 5 in
Now, in the wall itself, we want to find the value of the length "b".
This length represents the long side in the prototype used in building the wall.
Therefore:
b = 8 in
Part (3):Looking at Dakota's wall, we can note that its height is formed from three bricks each having the height "b". We have deduced previously that b = 8 in.
Therefore:
height of wall = 3 * b
height of wall = 3 * 8 = 24 in
Part (4):Looking at Dakota's wall, we can note that its length is formed from nine bricks each having a length "a". We have deduced previously that a = 5 in.
Therefore:
length of wall = 9 * a
length of wall = 9 * 5 = 45 in
Hope this helps :)
Answer:
Area of ABCD = 959.93 units²
Step-by-step explanation:
a). By applying Sine rule in the ΔABD,


Sin∠DBA = 
m∠DBA = 
m∠DBA = 45.64°
Therefore, m∠ADB = 180° - (110° + 45.64°) = 24.36°
m∠ADB = 24.36°
c). Area of ABCD = Area of ΔABD + Area of ΔBCD
Area of ΔABD = AD×BD×Sin(
)
= 35×46Sin(12.18)
= 339.68 units²
Area of ΔBCD = BD×BC×Sin(
)°
= 46×27×(0.4994)
= 620.25 units²
Area of ABCD = 339.68 + 620.25
= 959.93 units²
You would combine like this:
17e=18
Then divide off the sides
17e/17e 18/17e which cross out the 17 e which leaves you with 1.1
Answer:
29
Step-by-step explanation: