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2 years ago

Please Help me. I get so confused doing these questions.

Mathematics

1 answer:

ArbitrLikvidat [17]2 years ago

3 0

Answer:

It should be -24

Step-by-step explanation:

I found it online, since I wasn't entirely sure, but remember that studying can be fun, and everyone have an amazing day :)

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A 90 ° angle is divided into 2 angles. Find the size of the angles. 5x+10 and 6x-41 Not drawn to scale

Mrrafil [7]

Answer:

65 and 25

Step-by-step explanation:

90=(5x+10)+(6x-41)

121=11x

11=x

Going back to the angles:

5(11)+10

=55+10

=65 this is the first angle

6(11)-41

=66-41

25 this is the second angle

5 0

3 years ago

How can you solve quadratic equation in one variable using factoring method?

Tresset [83]

Take a quadratic equation in standard form:
If there exists a sum of two numbers that equal b, whose addends produce a product that equals c. You can rewrite the quadratic as a product of two binomials.

For example take
When thought through throughly, -5 had addends, -2 and -3 that produce 6 when multiplied
Thus, we can rewrite the quadratic as.

4 0

3 years ago

Drag the point A to the location indicated in each scenario to complete each statement.

Art [367]

The graph from which the position of the point A can determined following

the multiplication with a scalar is attached.

Responses:

If A is in quadrant I and is multiplied by a negative scalar, c, then c·A is in quadrant III

If A is in quadrant II and is multiplied by a positive scalar, c, then c·A is in quadrant II

If A is in quadrant II and is multiplied by a negative scalar, c, then c·A is in quadrant IV

If A is in quadrant III and is multiplied by a negative scalar, c, then c·A is in quadrant I

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, c, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

c·A = c·a + c·b·i is in the quadrant III (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar c, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

c·A = -c·a + c·b·i is in quadrant II

Multiplying A by negative scalar if A is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in quadrant IV

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying A with a negative scalar c gives;

c·A = c·a + c·b·i

c·a is positive

c·b is positive

Therefore;

c·A = c·a + c·b·i is in quadrant I

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

4 0

3 years ago

5x^(-2)-17x^(-1)+6 i’m so confused pls help will give brainliest

laila [671]

It's a quadratic equation in disguise. If you let $y=x^{-1}$ , then $y^2=x^{-2}$ , and we can rewrite the equation as

$5y^2-17y+6=0$

Solve for $y$ however you like; we get $y=\dfrac25$ and $y=3$ .

But we want to solve for $x$ , so we have

$y=x^{-1}=\dfrac25\implies x=\dfrac52$

$y=x^{-1}=3\implies x=\dfrac13$

5 0

3 years ago

How much would you need to deposit in an account now in order to have $4000 in the account in 10 years? Assume the account earns

gogolik [260]

Answer:

$2355.06

Step-by-step explanation:

Use the compound interest formula, filling in the numbers you know. Then solve for the number you don't know.

A = P(1 +r/n)^(nt)

where A is the account balance, P is the amount invested, r is the annual rate, n is the number of times per year interest is compounded, and t is the number of years.

Filling in the given values, we have ...

4000 = P(1 +.053/52)^(52·10) = P(1.6984738)

P = 4000/1.6984738 ≈ 2355.06

You would need to deposit $2355.06 in order to have $4000 in 10 years.

5 0

3 years ago