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worty [1.4K]
3 years ago
9

What scale factor was used to dilate Figure A to get Firgure B

Mathematics
2 answers:
Whitepunk [10]3 years ago
7 0
A scale factor of 3 was used
Dafna11 [192]3 years ago
7 0
A scale factor of 3 was used to dilate the figures.
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A manufacturing process is designed to produce bolts with a 0.25-in. diameter. Once each day, a random sample of 36 bolts is sel
Troyanec [42]

Answer:

0.6170

Step-by-step explanation:

Given that a manufacturing process is designed to produce bolts with a 0.25-in. diameter.

i.e. no of bolts which are produced as per standard is X means then

X is normal with mean = 0.250 and std dev = 0.04

No of bolts tested = 36

If this mean falls outside the interval (0.230,0.270) the production would be shut down.

i.e. P(|x-25|>0.20) =production shut down probability

P(|x-25|>0.20)\\=P(|Z|>0.5)\\=2(0.5-0.1915)\\= 0.6170

3 0
3 years ago
Please help,,, will give brainliest and five stars to correct answer
Zigmanuir [339]
Second option is the correct one.
-24, -96, -384, -1536, -6144, -24576
4 0
3 years ago
Read 2 more answers
NEED HELP QUICK NO LINKS PLEASE!
Juli2301 [7.4K]

Answer:

3. 4x^2y

Step-by-step explanation:

The GCF of 36 and 14 is 4.

The GCF of x^2y and x^2y^2 is x^2y

Multiply the two GCF and you get 4x^2y

6 0
3 years ago
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Sixteen students in a drama club want to attend a play. The tickect price is $ 35 for each student, and the transportation and m
guajiro [1.7K]
Because there is no cost for the sweatshirts, there is no way to solve this for the amount of sweatshirts needed. However, the amount of money each student needs to make off of them is $95. 
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3 years ago
Cards are dealt, one at a time, from a standard 52-card deck. a if the first 2 cards are both spades, what is the probability th
ratelena [41]
So we already drew two cards and both of them are spades. So that means there are 50 cards and 11 spades left.

Then third card being spades would be 11 / 50

Now there are 10 spades and 49 cards left.
So the probability for fourth card would be 10 / 49

Fifth card would be 9 / 48.

So the probability of next three cards being spades would be
\dfrac{11}{50}\cdot\dfrac{10}{49}\cdot\dfrac9{48}=\dfrac{33}{3920}\approx\boxed{0.00842}

Hope this helps.
3 0
3 years ago
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