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gladu [14]
3 years ago
6

7. Algebra

Mathematics
2 answers:
Dafna11 [192]3 years ago
6 0

Answer:

M=6

Step-by-step explanation:

Drupady [299]3 years ago
5 0

Answer:

Step-by-step explanation:

-6m+4=-32 subtract 4 from both sides

-6m=-36 divide both sides by -6

m=6

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4. How many real-number solutions does the equation have?
erma4kov [3.2K]
2 solutions. This is because the parabola will cross the x axis twice. We know this because -5 means the vertex will be 5 units below the x axis. and the parabola opens upwards because the first coefficient is positive. Hope this helped :)
5 0
4 years ago
You bike 1 mile the first day of your​ training, 1.3 miles the second​ day, 1.9 miles the third​ day, and 3.1 miles the fourth d
JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

d_1=1 mi is the distance travelled during the 1st day

d_2=1.3 mi is the distance travelled during the 2nd day

d_3=1.9 mi is the distance travelled during the 3rd day

d_4=3.1 mi is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2

Which can be rewritten using the general formula:

d_{n+1}-d_n=2(d_n-d_{n-1})

This means that

d_{n+1}=d_n+2(d_n-d_{n-1})

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi

So, the  distance travelled on the 7th day is 19.9 miles.

7 0
4 years ago
A line has a slope of –3 and a y-intercept of (0, –1). What is the equation of the line that is parallel to the given line and p
givi [52]
Well, the first line has a slope of -3, and runs through 0, -1.

a line parallel to that one, will have the same exact slope of -3.

now, we know about this other parallel line that it runs through -3,1, and of course, since is parallel, it has a slope of -3

\bf \begin{array}{ccccccccc}
&&x_1&&y_1\\
&&(~ -3 &,& 1~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies -3
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=-3[x-(-3)]
\\\\\\
y-1=-3(x+3)
\implies 
y-1=-3x-9\implies y=-3x-8
6 0
4 years ago
I need help plsss I will give u more points
lions [1.4K]

Answer:

  1. The value of 0.9* 10² is <u>D</u><u>.</u><u>9</u><u>0</u><u>.</u>
  2. <u>4</u><u>*</u><u>(</u><u>1</u><u>2</u><u>-</u><u>8</u><u>)</u><u>+</u><u>2</u><u>³</u>
  • 4*4+2³
  • 16+8
  • 24

a.

<u>False</u><u> </u><u>:</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>to</u><u> </u><u>add</u><u> </u><u>1</u><u>6</u><u>+</u><u>8</u>

<u>b</u><u>.</u>

<u>False</u><u> </u><u>:</u><u> </u><u>its</u><u> </u><u>8</u><u>.</u>

<u>c</u><u>.</u>

<u>True</u><u>.</u>

<u>d</u><u>.</u>

<u>False</u><u> </u><u>:</u><u> </u><u>its</u><u> </u><u>2</u><u>4</u><u>.</u>

<u>3</u><u>.</u>

<u>side</u><u> </u><u> </u> of cube [a]=2ft

volume of cube [V]=a³=2³=8ft³

<u>He</u><u> </u><u>needs</u><u> </u><u>1</u><u> </u><u>bag</u><u> </u><u>to</u><u> </u><u>buy</u><u>.</u><u>As</u><u> </u><u>its</u><u> </u><u>volume</u><u> </u><u>is</u><u> </u><u>equal</u><u>.</u>

7 0
3 years ago
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

       S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= <u> 3690 - 3300 </u> = 2.549

       530/√12

The rejection region for this test is two-tailed, with critical values:

t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201

t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0
3 years ago
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