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Oksanka [162]
2 years ago
8

A paper hat is folded into the shape of a kite, as shown.

Mathematics
2 answers:
den301095 [7]2 years ago
7 0

Answer:

The answer is D.22

:)

Step-by-step explanation:


blondinia [14]2 years ago
4 0
3x + 5 = 5x + 1   because these 2 long lines are equal

2x = 4
x =  2

so length required is (3(2) + 5) * 2  = 22 in
You might be interested in
For a snack, sander ate a plum with 32 calories and several strawberries with 4 calories each. If the total number of calories i
muminat

Answer:

6 strawberries

You subtract 32 from 56, which gives you 24. Then, if one strawberry is 4 calories, you can eat 6 of them to gain 24 calories.

32 + 24 = 56 ... So one plum (32) and six strawberries (4+4+4+4+4+4) gives you 56 calories, which is the total. That's how you can check your work.

Answer: 6

4 0
3 years ago
Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw
PolarNik [594]

Answer:

Using <u>backward reasoning</u> we want to show that <em>"We can never get nine 0's"</em>.

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

<u>There were 9 </u><u>0's</u><u>:</u>

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

<u>There were 9 </u><u>1's</u><u>:</u>

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

<u />

5 0
3 years ago
(10-P) Help please, thanks.
Anuta_ua [19.1K]
The formula of linear equation is:
y1  -  y2 = m(x1  -  x2)
Where
x1 and x2: x coordinates(-1 and 3)
y1 and y2: y coordinates(-2 and 10)
m is the slope

We can then choose a point from the line to find the eqaution.

We need to first find the slope:
\frac{y1 - y2}{x1 - x2}
In this case:
\frac{ - 2 - 10}{ - 1 - 3}   \\ =  \frac{ - 12}{ - 4}  \\  = 3

In this case, as the y2 is given as 1,put (-1,-2) , and the slope(3 )into the eqaution :

y-(-2) = 3(x-(-1))
y+2 = 3(x+1)

Therefore
y + 2 = 3x + 1
is the answer.

Hope it helps!
7 0
3 years ago
I need some help on my homework
irakobra [83]
What do you need help with I cant help if I don't know what problems to solve
6 0
2 years ago
If y=3x+2,find the value of y when x=-3
Mars2501 [29]
Y=3x+2 when x=-3
=> y= 3(-3)+2 = -9+2 =-7
6 0
3 years ago
Read 2 more answers
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