Answer:
T + V = 50
2T + (3/2) * V = 90
2T + 1.5V = 90
T = 50 * 1.5 - 90 * 1 / 1 * 1.5 - 2*1 = 30
V = 1 * 90 - 2 * 50 / 1 * 1.5 - 2 * 1 = 20
Step-by-step explanation:
T = 30
V = 20
Answer:

Step-by-step explanation:

It’s the ratio of pt to p’t’ is
Answer:
Any value of x
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Step-by-step explanation:
Given


Required
What value of x is 
Solving for f(g(x))


Solve the inner square



Solving g(f(x))





Equate f(g(x)) and g(f(x))


<em>This implies that </em>
<em> at any value of x</em>