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artcher [175]
3 years ago
8

2^8-x+16=15 HELLO! How is everyone lately?

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
6 0

Answer:

I’m fine ig,

how are you doin?

Step-by-step explanation : )

alina1380 [7]3 years ago
3 0

Answer:

x = 257

Step-by-step explanation:

2^8 - x + 16 =15

256 - x + 16 = 15

256 + 16 - 15 = x

257 = x

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Show all the stepsx: 3, 9, 13, 20y: 9, 27, 39, 60State whether the relationship between the variables in the table is a direct v
a_sh-v [17]

By looking at the table, we can see that the y values are equal to the x values multiplied by 3.

3x = 3*3 = 9

3x =3*9 = 27

3x=3*13=39

3x= 3*20= 60

So, it is a direct variation and the function is y=3x

6 0
1 year ago
there are 60 teams attend a chess tournament. every team will play with every other team exactly once. Supposed each team has a
Karolina [17]

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

The reason for arriving at the above probability is as follows:

The given parameters are;

The number of teams in the tournament, n = 60

The chance of a team winning a game = 50% = 0.5

The number of ties = No ties

The required parameter:

The probability that no two teams win the same number of games

Method:

Calculate the number of ways no two teams win the same number of games, and divide the result by the total number of possible outcomes

Solution:

The number of matches played, n = \dbinom {60} {2} = 1,770

The possible outcomes = 2; Winning or losing

The total number of possible outcomes, n_p = 2¹⁷⁷⁰

The number of games won by each team is between 0 and 59

The ways in which no two teams won the same number of games is given by the games won by the teams to be 0, 1, 2,..., 57, 58, 59

Therefore, the number of ways no two teams won the same number of games, the required outcomes, n_k = 59!

Probability = \dfrac{Number \ of \ possible \ outcomes}{Number \ of \ required\ outcomes}

The probability that no two teams win the same number of games is given as follows;

\mathbf{P(No \ two \ teams \ won \ the \ same \ number \ of \ games)} = \dfrac{n_k}{n_p}

Therefore;

P(No \ two \ teams \ won \ the \ same \ number \ of \ games) = \dfrac{59!}{2^{1,770}} \approx \mathbf{2.084 \times 10^{-453}}

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

Learn more about probability theory here:

brainly.com/question/1539712

3 0
3 years ago
Need help ASAP!!!( Algebra 1)
Sphinxa [80]

Answer:

[negitive]56 plus positive 56+15=-15

Step-by-step explanation:

i explained it up there

5 0
3 years ago
The value of a car with an initial purchase price of $15,250 depreciates by 16% per year. How much is the car worth after 6 year
Scrat [10]

Answer:

$13842.43

Step-by-step explanation:

Given data

Value of car=$15,250

Rate of depreciation= 16%

Time = 6 years

We can use the exponential function below to model the value of the car after 6 years

v(t)= a(r)^x

But r= 1-0.016----------Because the value is depreciating

a=15,250  

r=0.016  

x=6

Substitute

v(t)= 15250(1-0.016)^6

v(t)=  15250(0.984)^6

v(t)=  15250*0.9077

v(t)= $13842.43

Hence the value will be $13842.43 after 6 years

8 0
3 years ago
What is the answer for |x|=9
Maru [420]

The absolute value |x| returns the "positive version" of a number.

In other words, if the number is positive, it remains positive; if the number is negative, it changes sign.

So, if we want |x|=9, we want the "positive version" of x to be 9.

This can happen in two ways: if x is already 9, then its absolute value is still nine. If instead x=-9, its positive value will be 9 again.

In formula, we have

|x|=9 \iff x=\pm 9

because

|9|=9,\quad |-9|=9

8 0
3 years ago
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