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hichkok12 [17]
3 years ago
12

Please help me understand how to do this and the answer!

Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0
Turn F(x) into vertex form:

y=x^2+8x+6
y-6=x^2+8x
y-6+16=x^2+8x+16
y+10=(x+4)^2
Thus the vertex is (-4,-10)

This is a minimum because the parabola is up up, or is positive
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I am giving brainlist to quickest and the correct answer
Natalka [10]

Answer:

50

Step-by-step explanation:

Sally drove 300 miles in 6 hours, so all you have to do is divide 300 by 6.

300/6=50

Sally drove 50 miles per hour.

Have an amazing day...I hope this helped!! c:

5 0
3 years ago
Read 2 more answers
Here are the dimensions of the oven tray Jenny bakes the cakes on. Each cake tin is 25 cm in diameter. How many cake tins can Je
goldenfox [79]
Dimensions please? Hahaha :')
6 0
3 years ago
How do I do this it is a histogram problem the work is on the pictures
Dafna11 [192]
You have to measure it
4 0
3 years ago
8. myles had 103 coins in a jar - all nickels, dimes, and quarters. if the total value of the coins is $15
Ivanshal [37]

If the total value of the coins is $15. The number of each type of coin is: 31 quarters, 72 dimes.

<h3>Number of each type of coin</h3>

Let D = number of dimes

Let Q = the number of quarters

Equations

d + q = 103

0.10d + 0.25q = 15  

d = 103 -q

0.10(103 -q) + 0.25q = 15

10.3 - 0.10q + 0.25q = 15

0.15q = 4.7

q=4.7/0.15

q=31 quarters

Substitute q into second equation

D+31=103

D=72 dimes

Therefore the number of each type of coin is: 31 quarters, 72 dimes.

Learn more number of each coin here:brainly.com/question/13934075

#SPJ1

5 0
2 years ago
she sells 6adult tickets and 5 children tickets on the first day totaling $112.50 and on the second day she sells 8adult tickets
Leya [2.2K]

Answer:

Cost of adult ticket = $12.5

Cost of child ticket = $7.5

Step-by-step explanation:

Given:

Cost of 6 adult ticket and 5 child ticket = $112.5

Cost of 8 adult ticket and 4 child ticket = $130

Find:

Equation and solution

Computation:

Assume;

Cost of adult ticket = a

Cost of child ticket = b

So,

6a + 5b = 112.5....eq1

8a + 4b = 130 ......eq2

Eq2 x 1.25

10a + 5b = 162.5 .....eq3

eq3 - eq1

4a  = 50

Cost of adult ticket = $12.5

8a + 4b = 130

8(12.5) + 4b = 130

Cost of child ticket = $7.5

7 0
3 years ago
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