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den301095 [7]
4 years ago
8

The formula to find the period of orbit of a satellite around a planet is T2=(4π2GM)r3 where r is the orbit’s mean radius, M is

the mass of the planet, and G is the universal gravitational constant. If you are given all the values except r, how do you rewrite the formula to solve for r?
Mathematics
1 answer:
liq [111]4 years ago
8 0
The formula of the 3rd Kepler`s Law:
T ^{2} =  \frac{4 \pi  ^{2}r ^{3}  }{GM}
4 \pi ^{2} r ^{3} = T^{2}GM \\ r^{3}  = \frac{T ^{2} GM}{4 \pi^{2} }  \\ r =  \sqrt[3]{ \frac{T ^{2}GM }{4 \pi  ^{2} } }
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What is the solution to the equation 7 −3x ≈ 9? (1 point)
Gnesinka [82]

Answer:

-16/3 will be the answer for this question

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3 years ago
You earn (4x+12) points after completing X levels of a video game and then lose (2x-5) points. Write an expression that represen
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does this help at all?
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3 years ago
In the figure, angle D measures 31⁰ and angle A measures 27⁰
Zielflug [23.3K]

Answer:

1)B:63°

2)A:59°

Step-by-step explanation:

1.ABC is a right triangle at C then angle ACB=90°(right angle)

Angle CAB=27°(see the given)

measure of the angles in any triangle is 180°

then angle CBA=

measure of all the angles - (measure ACB+measure CAB)

=180°-(90°+27°)

=63°

2. Same explanation of angle B:

in the right triangle DEF: angle DEF=90°

angle D=31°(given)

Then measure of angle A=180°-(angle E + angle D)

=180-(90+31)=59°

3 0
3 years ago
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What is the area of triangle ABC?
kondor19780726 [428]

Answer: 7 square units

Step-by-step explanation:

<!> Brainliest is appreciated! <!>

6 0
3 years ago
What is the factorization of 3x2 – 8x + 5?
ELEN [110]

we have

3x^{2} -8x+5

Equate the expression to zero to find the roots

3x^{2} -8x+5=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

3x^{2} -8x=-5

Factor the leading coefficient

3(x^{2} -(8x/3))=-5

Complete the square. Remember to balance the equation by adding the same constants to each side.

3(x^{2} -(8x/3)+(16/9))=-5+(16/3)

3(x^{2} -(8x/3)+(16/9))=(1/3)

Rewrite as perfect squares

3(x-(4x/3))^{2}=(1/3)

(x-(4x/3))^{2}=(1/9)

square roots both sides

(x-\frac{4}{3})=(+/-) \sqrt{\frac{1}{9}}

x=\frac{4}{3}(+/-) \frac{1}{3}

the roots are

x=\frac{4}{3}+ \frac{1}{3}=\frac{5}{3}

x=\frac{4}{3}- \frac{1}{3}=\frac{3}{3}=1

so

3x^{2} -8x+5=3(x-\frac{5}{3})(x-1)=(3x-5)(x-1)

therefore

<u>the answer is the option</u>

(3x-5)(x-1)

6 0
3 years ago
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