Answer:

Step-by-step explanation:
OPQ is a right angle triangle.
<u>Using Pythagoras</u>

<u>Using quadratic formula</u>
<u />

OR
(Length can't be negative)
∴ 
20 is the greatest common factor
Each group of 20 will have 1 brownie & 5 cookies
M1= -5 , m2 = 5 inorder to get this you move the constant to the right take the root of both sides separate the solutions and you should get m1= -5, m2 =5
Step-by-step explanation:
The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:

Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.
So


Average velocity is 0.5 sec
To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.
We already found this, so I don't need more work (it's displayed above).
The instantaneous velocity when
is 2.5 sec.
Answer:
Step-by-step explanation:
- Initial number = 10
- Weekly growth rate = 15% or 1.15 times
<u>Equation for this relationship:</u>
- V(t) = 10*1.15^t, where t - number of weeks
<u>Number of views in 5 weeks:</u>
- V(5) = 10*1.15^5 = 20 views (rounded)