Answer:
4:18 pm
Step-by-step explanation:
An airport offers 2 shuttles that run on different schedules.If both shuttles leave the airport at 4:00 p.m.,at what time will they next leave theairport together.
Shuttle A leaves every 6 minutes
Shuttle B leaves every 9 minutes
Solution
To solve for when next both shuttles will leave the airport together, find the least common multiples of 6 minutes and 9 minutes
Shuttle A (every 6 minutes) = 6, 12, 18, 24
Shuttle B (every 9 minutes) = 9, 18, 27, 36
The least common multiples of 6 minutes and 9 minutes is 18 minutes
4:00 pm + 18 minutes
= 4:18 pm
The next time both shuttles will leave theairport together is 4:18 pm of the same day
360 is the anwer because i multipled 40 white cars by 9 times yellow car to get answer 40×9=360
Answer:
h. 36
Step-by-step explanation:
For a 68.26% confidence, z = 1.0.
Standard deviation (s) = 30 minutes
The sample size needed to assure that the sample mean does not differ from the true mean by more than 5 minutes is given by:
The sample size needed is 36.
A trapezoid does not have 2 pair of parallel sides so we can cross that out. A rhombus does not have right angles so cross that out. So we got A and C. A square has 2 pair of parallel lines and and 4 right angle. Your answers should be.
<span>C. Square
It could not be A. Most likely its C. So you can pick both or just C.</span>
