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Leni [432]
2 years ago
9

Tell whether (-4, 3) is a solution of the system of linear inequalities.

Mathematics
1 answer:
sergey [27]2 years ago
4 0
<h3>Answer:  No, it is not a solution</h3>

Explanation:

Refer to the diagram below. The point (-4,3) marked in red is outside the blue shaded region. So it doesn't make both inequalities true, and therefore not considered a solution.

In contrast, a point like (-5,1) is a solution as it is in the shaded region.

Put another way, the set of all solution points must be below both the solid line and the dashed line. Points can be on the solid line, but must be adjacent to the blue shaded region. The fact (-4,3) is on the solid line doesn't count because its not below the dashed line.

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<h3>your answer will be A</h3>

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Step-by-step explanation:

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Pls help! I'm confused. Can you explain this if you can.
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Answer:

From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. From a <u>graph</u>, the y-intercept will not be <u>zero</u>.  From an equation, it will have the form, y = mx + b where b is <u>≠ 0</u>.

Step-by-step explanation:

  • From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. If there is not a constant rate of change in the data displayed in a table, then the table represents a nonlinear nonproportional relationship.
  • From a <u>graph</u>, the y-intercept will not be <u>zero</u>. This means that it doesn't contain or go through the origin.  
  • From an equation, it will have the form, y = mx + b where b is <u>≠ 0.</u> (not equal to zero). If an equation is not a linear equation, it represents a nonproportional relationship. A <u>linear equation</u> of the form y = mx + b may represent either a <em>proportional</em> (b = 0) or <em>nonproportional</em> (b ≠ 0) relationship.  Therefore, when b ≠ 0, the relationship between <em>x</em> and <em>y</em> is <u>nonproportional</u>.
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