Answer:
So the inner function is g(x) = arctan(x) and the outer function is h(x) = e^(x)
Step-by-step explanation:
Suppose we have a function in the following format:
f(x) = g(h(x))
The inner function is h(x) and the outer function is g(x).
In this question:
f(x)=arctan(e^(x))
From the notation above
h(x) = e^(x)
g(x) = arctan(x)
Then
f(x) = g(h(x)) = g(e^(x)) = arctan(e^(x))
So the inner function is g(x) = arctan(x) and the outer function is h(x) = e^(x)
Answer:
The given equation 3x^2-4x+21 has no factors.
Step-by-step explanation:
We need to factorize this equation.
For factorization we split the middle term such that their sum is equal to middle term and product is equal to product of first and last term of the given expression.
in Our case : 63x^2
We need to find two factors of 63x^2 whose sum is equal to -4x
Factors of 63= 1,3,7,9,21,63
1* 63
3*21
7*9
None of the above factors sum is equal to -4.
So, the given equation 3x^2-4x+21 has no factors.
The answer is (0,0) to (0, -5) I hope this helped ^^