Give EG = 5x+7 EF =5x and FG=2x-7
1 answer:
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Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)
=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Answer:
x = 9.818
x≈10
The number of banners that can be made are 10
Step-by-step explanation:
We can use the knowledge of proportion to solve this.
First we need to convert yard to feet.
1 yard = 3 foot
4 1/2 yard = y
cross-multiply
y = 4 1/2 × 3
=9/2 × 3
y = feet
This implies 4 1/2 yards = feet
Let x be the numbers of banners needed to make from 4 1/2 yards of fabric.
1 3/8 feet = 1 banner
feets = x
cross multiply
1 3/8 × x =
=
cross-multiply
22x = 216
Divide both-side of the equation by 22
22x/22 = 216/22
x = 9.818
x≈10
The number of banners that can be made are 10
Answer:
48+23(6)½
Step-by-step explanation:
A = l × w
A =[(8-(6)^½) × (9+4(6)^½)]
A =8(9+4(6)^½) + [-(6)^½(9+4(6)^½]
A =(72 + 32(6)^½ - 9(6)^½ - 24)
A =(72 - 24 + 32(6)^½ - 9(6)^½)
A =(48 + 23(6)^½)
