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Marianna [84]
3 years ago
14

Give EG = 5x+7 EF =5x and FG=2x-7

Mathematics
1 answer:
Len [333]3 years ago
7 0

Answer:

x = 7

42, 35, 7

Step-by-step explanation:

  • EG = 5x+7
  • EF = 5x  
  • FG = 2x-7

Point F is on line segment of EG, therefore EG = EF + FG

  • 5x + 7 = 5x + 2x - 7
  • 2x = 14
  • x = 7

Then

  • EG = 5*7 + 7 = 42
  • EF = 5*7 = 35
  • FG = 2*7 - 7 = 7
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a can of cola says dat it contain 330ml a food inspector carefully measures d content of a can and find that it conatins 341ml.
daser333 [38]

Answer:

3.33%

Step-by-step explanation:

Factory measure=330 ml

Actual measure=341 ml

Difference between actual measure and factory measure is error

Difference=341 ml-330 ml=11 ml

Error (in ml)=11 ml

Percentage error=100* Error/Factory measure

Percentage error= 100*\frac {11 ml}{330}%

Percentage error=3.33%

Therefore, the percentage error in the content is 3.33%

7 0
4 years ago
At Ajax Spring Water, a half-liter bottle of soft drink is supposed to contain a mean of 519 ml. The filling process follows a n
k0ka [10]

Answer:

1) The normal distribution should be used for the sample mean because the population distribution is known to be normal (answer b).

2) C. H0: mu = 519, H_1: mu not equal to 519, reject if z> 1.96 or z< -1.96.

3) Yes. There is enough evidence to support the claim that the true mean is not 519 ml.

Step-by-step explanation:

1) When the population follows a normal distribution, it is correct to assume a normal distribution for the sample mean.

2) As it is a two-tailed decision rule, we are interested in detecting a significant difference below and above the mean. This is why we use the unequal sign in the alternative hypothesis.

The null hypothesis state that there is not significant difference from 519.

The critical value for a significance level of 5% is z=1.96.

H_0: \mu=519\\\\H_a:\mu\neq 519

3) The claim is that the true mean is not 519 ml.

Then, the null and alternative hypothesis are:

H_0: \mu=519\\\\H_a:\mu\neq 519

The significance level is 0.05.

The sample has a size n=16.

The sample mean is M=522.

The standard deviation of the population is known and has a value of σ=6.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{16}}=1.5

Then, we can calculate the z-statistic as:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{522-519}{1.5}=\dfrac{3}{1.5}=2

This test is a two-tailed test, so the P-value for this test is calculated as:

\text{P-value}=2\cdot P(z>2)=0.046

As the P-value (0.046) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the true mean is not 519 ml.

7 0
3 years ago
Help with my math!!!!!!
shusha [124]
Pretend DK and ML are parallel lines. Then MK is a line crossing the parallel lines. Angles KML and DKM would be alternate interior angles there fore the angle would be the same, 82.
8 0
4 years ago
Combining like terms<br> 2 + 3x - X=4x
ololo11 [35]

Answer:

Hi there!

Your answer is:

x= 1

Step-by-step explanation:

Goal- get all X's on one side, and all whole numbers on the other

2+3x -x = 4x

First, combine like terms on each side of the equal sign

2+ 2x = 4x

Next, think about the additive inverse property. What, added to 2x, equals 0? 2x + (-2x) =0! So, we <u>subtract</u> 2x from both sides!

2= 4x-2x

Simplify

2= 2x

Divide both sides by the coefficient of x (in this case, 2)

2/2 = x

2/2 is equal to 1

1= x

Hope this helps!

8 0
3 years ago
Read 2 more answers
If MS = 20 m, MT = 9 m, and RM = 12 m, what is the value of IM?
Helga [31]
Given two similar right triangles MIT and MSR such that side MR is an extension of side MT, side MS is an extension of side MI and the side IT is parallel to side SR.

Also, give that <span>If MS = 20 m, MT = 9 m, and RM = 12 m. To find the value of IM, we recall that the ratio of any two sides of a similar figure is equal to the ratio of the corresponding sides of the other triangle.

i.e. IM / MT = MS / RM
</span> IM / 9 = 20 / 12
IM = (9 x 20) / 12 = 15

Therefore, the measure of side IM is 15 m.
3 0
3 years ago
Read 2 more answers
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