Which postulate can be used to prove the two triangles are congruent?

A jar contains some bacteria. Every day the number of bacteria

svp [43]

Answer:

Day 2

Step-by-step explanation:

Every 20 days, one jar is full.

To find when it was 1/8 full, we multiply the 20 days by 1/8.

20 x 1/8 = 2

Day 2

3 0

2 years ago

What is the value of 3 3/8 +1/2÷4/5x2 (Please help...i will make BRAINLIEST)

Agata [3.3K]

Answer:

4 5/8

Step-by-step explanation:

4.625

3 0

3 years ago

Read 2 more answers

A rectangle has a perimeter 204 it’s length six feet longer than twice it’s width if L stands for the rectangle and W stands for

andriy [413]

Answer:

W=32

L=70

Step-by-step explanation:

L=2w+6

204=2L+2W

204=2w+2(2w+6)

204=2w+4w+12

192=6w

w=32

L=2(32)+6

L=70

6 0

3 years ago

A survey showed that 77% of us need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. 13 adults are randomly

earnstyle [38]

Using the binomial distribution, it is found that the probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

For each person, there are only two possible outcomes, either they need correction for their eyesight, or they do not. The probability of a person needing correction is independent of any other person, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

A survey showed that 77% of us need correction, hence p = 0.77.

13 adults are randomly selected, hence n = 13.

The probability that at least 12 of them need correction for their eyesight is given by:

$P(X \geq 12) = P(X = 12) + P(X = 13)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{13,12}.(0.77)^{12}.(0.23)^{1} = 0.1299$

$P(X = 13) = C_{13,13}.(0.77)^{13}.(0.23)^{0} = 0.0334$

Then:

$P(X \geq 12) = P(X = 12) + P(X = 13) = 0.1299 + 0.0334 = 0.163$

The probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

More can be learned about the binomial distribution at brainly.com/question/24863377

7 0

2 years ago

Construct 3 linear equation starting with qiven solution z = 1/3

Andreyy89

Answer:

(a) $9z+2=5$