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2 years ago

Which postulate can be used to prove the two triangles are congruent?

Mathematics

1 answer:

Trava [24]2 years ago

6 0

Answer:

ASA

Step-by-step explanation:

ANGLE SIDE ANGLE IS SUITBLE

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In 2009 the number of vehicle sales in the United States was 10,002 thousand and in 2013 it was 17,884 thousand.a. [3 pts] Deter

anygoal [31]

Answer:

1970.5 thousand

Step-by-step explanation:

Given

Vehicle sales in 2009 = 10,002 thousand

Vehicle sales in 2013 = 17,884 thousand

Required

Determine the average rate of change;

From the given parameters, it can be seen that the number of vehicles is a function of year

Let x represent the years and y represent the number of vehicles;

Such that;

$x_1 = 2009;\ y_1 = 10,002$

$x_2 = 2013;\ y_2 = 17,884$

The rate of change is calculate as follows;

$m = \frac{y_1 - y_2}{x_1 - x_2}$

$m = \frac{10002 - 17884}{2009 - 2013}$

$m = \frac{-7882}{-4}$

$m = 1970.5$

Hence, the average rate of change is 1970.5 thousand

6 0

3 years ago

I will give branly to the best and fast answer :D

Anton [14]

Answer:

its fifteen fiths

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

How to do the problem

marta [7]

There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
$8 \frac{1}{4} + 9 \frac{1}{4} + 8 \frac{7}{8} + 9 \frac{5}{8} + 10 \frac{3}{4}$
$= \frac{8 \times 4 + 1}{4} + \frac{9 \times 4 + 1}{4} \\ + \frac{8 \times 8 + 7}{8} + \frac{9 \times 8 + 5}{8} \\ + \frac{10 \times 4 + 3}{4}$
$= \frac{33}{4} + \frac{37}{4} + \frac{71}{8} + \frac{77}{8} + \frac{43}{4} \\ = \frac{33 \times 2}{4 \times 2} + \frac{37 \times 2}{4 \times 2} + \frac{71}{8} \\ + \frac{77}{8} + \frac{43 \times 2}{4 \times 2}$
$= \frac{66 + 74 + 71 + 77 + 86}{8}$
$= \frac{374}{8} = \frac{186}{4}$
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
$\frac{186 - 153}{4} = \frac{33}{4} = 8 \frac{1}{4}$

The leftover watermelon is 8 & 1/4 pounds.

6 0

2 years ago

Ms. jada wants to save money for her spring break trip. She already has $400 saved in her account. She needs $1600 for the entir

valkas [14]

Answer:

1600-400

=1200

1200/300

=4 months

3 0

2 years ago

Read 2 more answers

A conical vessels with base radius 5 cm and height 24cm is full of water this water is emptied into a cylindrical vessel of base

Aliun [14]

Answer:

$2\ cm$

Step-by-step explanation:

$We\ are\ given\ that,\\Radius\ of\ the\ conical\ vessel=5\ cm\\Height\ of\ the\ conical\ vessel=24\ cm\\Hence,\\As\ we\ know\ that,\\Volume\ of\ a\ cone=\frac{1}{3}\pi r^2h\\Hence,\\The\ volume\ of\ the\ conical\ vessel=\frac{1}{3}\pi (5)^224= \frac{1}{3}\pi 25*24=200\pi \\Hence,\\The\ volume\ of\ the\ conical\ vessel=The\ amount\ of\ water\ filled\ in\ it\\Hence,\\The\ amount\ of\ water\ filled\ in\ the\ conical\ vessel=200\pi\\Lets\ consider\ the\ cylindrical\ vessel:\\Volume\ of\ a\ cylinder=\pi r^2h$

$As\ we\ are\ not\ said\ that\ the\ cylindrical\ vessel\ was\ empty,\ let\ its\ initial\\ height\ be\ h_1\\Radius\ of\ the\ Cylindrical\ vessel=10\ cm\\Initial\ height\ of\ the\ cylindrical\ vessel=h_1\\Initial\ volume\ of\ the\ cylindrical\ vessel=\pi *10^2*h_1=100h_1\pi \\Initial\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi \\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=Final\ amount\ of\ water\\ in\ the\ cylindrical\ vessel +Amount\ of\ water\ in\ conical\ vessel$

$Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi +200\pi \\Now,\\Let\ the\ final\ height\ be\ h_2\\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=\pi *10^2*h_2=100h_2\pi \\Hence,\\100h_2\pi =100h_1\pi +200\pi \\Hence,\\100h_2=100h_1+200\\100h_2-100h_1=200\\100(h_2-h_1)=200\\h_2-h_1=2\\Hence,\\As\ the\ rise\ in\ level\ is\ the\ difference\ between\ the\ initial\ and\ final\\ heights:\\The\ rise\ in\ level\ of\ water=2\ cm$

8 0

2 years ago