Hi! I'm confused with this question, It's about tessellations. Can someone give a complete example of a possible answer? It woul
d be much appreciated! I MAY give brainliest.
To make it easier for people with the same problem to find this I'm gonna include this: c) Create an irregular tessellation using the grid below by modifying one of the squares, performing a glide reflection, and continuing the pattern to fill the grid. (10 points)
To make it easier for people with the same problem to find this I'm gonna include this: c) Create an irregular tessellation using the grid below by modifying one of the squares, performing a glide reflection, and continuing the pattern to fill the grid. (10 points)
1 answer:
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Answer:
Step-by-step explanation:
We are given that:
Where <em>A</em> is in QI.
And we want to find sec(A).
Recall that cosecant is the ratio of the hypotenuse to the opposite side. So, find the adjacent side using the Pythagorean Theorem:
So, with respect to <em>A</em>, our adjacent side is 63, our opposite side is 16, and our hypotenuse is 65.
Since <em>A</em> is in QI, all of our trigonometric ratios will be positive.
Secant is the ratio of the hypotenuse to the adjacent. Hence:
Answer:
A, C, D and K
Step-by-step explanation:
Inequalities:
y ≤ −2x + 10 and y >1/2x-2
<u>Finding zeros for the first inequality:</u>
- x=0 ⇒ y= 10, point (0, 10)
- y=0 ⇒ x= 5, point (5, 0)
- Locating these 2 points and connecting to get the first line.
Space to the left of this line (as y≤ ) is the solution for this inequality, any points on this line are inclusive.
<u>Finding zeros for the second inequality:</u>
- x=0 ⇒ y= -2, point (0, -2)
- y= 0 ⇒ x= 4, point (4, 0)
- Locating these points and connecting to get the second line.
Space above this line (as y > sign) is the solution for this inequality, any points on this line are not inclusive.
Now we have the space of intersection of the above inequalities.
So the points in same section are the solution.
They are:
- Points A, C, D and K
See attached for explanation
