If you know that -2 is a zero of f(x) = x^3 + 7x^2 + 4x - 12, explain how to solve the equation.
First you have to figure out what could make f(x) = 0 to get rid of the cube. I'm going to test the array of data, x = -2, x = -3, and x = -4 because this type of equation probably has more negative values given that if you plug in some values the cubed-values and squared-values will surpass the "-12". Plug this into a calculator.
x^3 + 7x^2 + 4x - 12
f(-2) = -8 + 28 - 8 - 12 = 0
So you know that when x = -2, f(x) = 0. Divide "(x + 2)" from the equation and you will get... x^2 + 5x - 6. Now this is a simple polynomial one that you can figure to be (x + 6) (x - 1) just by looking at it because -6 multiplied by 1 is negative 6 and you see 5 and know that 6 - 1 = 5.
The solution is (x + 6) (x - 1) (x + 2) meaning that when x = -6, 1, or -2, f(x) is 0.
Answer:
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The third one.
Because the answer of the absulate value equations is always positive.
Answer:
15,015
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the age be xy or 10x + y.
Reverse the two digits of my age, divide by three, add 20, and the result is my age, convert this to equation:
- (10y + x)/3 + 20 = 10x + y
- (10y + x)/3 = 10x + y - 20
- 10y + x = 3(10x + y - 20)
- 10y + x = 30x + 3y - 60
- 30x - x + 3y - 10y = 60
- 29x - 7y = 60
We should consider both x and y are between 1 and 9 since both the age and its reverse are 2-digit numbers.
Possible options for x are:
- 29x ≥ 7*1 + 60 = 67 ⇒ x > 2, at minimum value of y,
and
- 29x ≤ 7*9 + 60 = 123 ⇒ x < 5, at maximum value of y.
So x can be 3 or 4.
<h3>If x = 3</h3>
- 29*3 - 7y = 60
- 87 - 7y = 60
- 7y = 27
- y = 27/7, discarded as fraction.
<h3>If x = 4</h3>
- 29*4 - 7y = 60
- 116 - 7y = 60
- 7y = 56
- y = 8
So the age is 48.
