Find the measure of the indicated angle to the nearest degree

The image above is an example of which type of fossil

Aleksandr [31]

This is an example of fossil preserved in amber.

Amber is a polymerized form of tree resin, produced by the trees so as to protect themselves against diseases and insect pests. This resin hardened and sometimes captured insects, microorganisms, plants, seeds and feathers, spiders, and other small vertebrates that got stuck in the sticky resin.

7 0

3 years ago

Determine if the lines are parallel, perpendicular or neither. -2x + y = -4 and -19 - y = 1/2x

LekaFEV [45]

The lines are perpendicular because the slopes are negative reciprocals of eachother.

8 0

3 years ago

Need help getting stuck on this problem

stepan [7]

Answer:

Variable x in first equation

Step-by-step explanation:

Given system

x = 5y - 1
x + 2y = 13

Variables in this system are x and y.

Isolating a variable means rearranging the equation so that a variable of our interest is on its own in one side of the equal sign.

We see variable x is isolated in the first equation.

In the second equation both of the variables are on the same side so they are not isolated.

3 0

3 years ago

Please help on stuck on this problem

Damm [24]

Answer:

The answer is b

Step-by-step explanation:

If you do the square root button for both 729 is 27

and 862 is 29.36

3 0

3 years ago

Read 2 more answers

The United States Coast Guard assumes the mean weight of passengers in commercial boats is 185 pounds. The previous value was lo

Valentin [98]

Answer:

There is a 5.5% probability that a random sample of passengers will have a mean weight that is as extreme or more extreme (either above or below the mean) than was observed in this sample.

Step-by-step explanation:

To solve this problem, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

In this problem, we have that:

$\mu = 185, \sigma = 26.7, n = 48, s = \frac{26.7}{\sqrt{48}} = 3.85$

The weights of a random sample of 48 commercial boat passengers were recorded. The sample mean was determined to be 177.6 pounds. Find the probability that a random sample of passengers will have a mean weight that is as extreme or more extreme (either above or below the mean) than was observed in this sample.

The probability of an extreme value below the mean.

This is the pvalue of Z when X = 177.6.

So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{177.6 - 185}{3.85}$

$Z = -1.92$

$Z = -1.92$ has a pvalue of 0.0274.

So there is a 2.74% of having a sample mean as extreme than that and lower than the mean.

The probability of an extrema value above the mean.

Measures above the mean have a positive z score.

So this probability is 1 subtracted by the pvalue of $Z = 1.92$

$Z = 1.92$ has a pvalue of 0.9726.

So there is a 1-0.9726 = 0.0274 = 2.74% of having a sample mean as extreme than that and above than the mean.

Total:

2*0.0274 = 0.0548 = 0.055

There is a 5.5% probability that a random sample of passengers will have a mean weight that is as extreme or more extreme (either above or below the mean) than was observed in this sample.

4 0

3 years ago