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2 years ago

Six movie tickets cost $96 what is the cost per ticket

Mathematics

2 answers:

zimovet [89]2 years ago

7 0

Cost of 6 tickets = $ 96

Cost of 1 ticket = ?

Cost of 1 ticket = 96/6

Cost per ticket = $ 16

______

Hope it helps ⚜

zavuch27 [327]2 years ago

3 0

Step-by-step explanation:

6 tickets=$96

1 ticket =96/6

=16

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Use the formula for the cosine of the difference of two angles to find the exact value of the following expression.

Zolol [24]

Answer:

Exact value of Cos(45° - 60°) is 0.96 using difference of two angles.

Step-by-step explanation:

Given:

Cos(45° - 60°)

We have to apply the formula of cosine for difference of the two angles.

Formula:

$cos(a-b)=cos(a)\ cos(b)+sin(a)\ sin(b)$

Plugging the values.

⇒ $cos(45-60)=cos(45)\ cos(60) + sin(45)\ sin(60)$

We know that the values :

$sin(45) =cos(45) = \frac{1}{\sqrt{2} }$

$sin(60)=\frac{\sqrt{3} }{2}$ and $cos(60)=\frac{1}{2}$

So,

⇒ $cos(45-60)=(\frac{1}{\sqrt{2} } \times \frac{1}{2} ) + (\frac{1}{\sqrt{2} } \times \frac{\sqrt{3} }{2})$

⇒ $cos(45-60)=(\frac{1}{2\sqrt{2} } + \frac{\sqrt{3} }{2\sqrt{2} })$

⇒ $cos(45-60)=(\frac{1+\sqrt{3} }{2\sqrt{2} } )$

⇒ $cos(45-60)=(\frac{1+\sqrt{3} }{2\sqrt{2} } )\times \frac{2\sqrt{2} }{2\sqrt{2} }$ ...rationalizing

⇒ $cos(45-60)=\frac{2\sqrt{2} +2\sqrt{6} }{ 8}$

⇒ $cos(45-60)=\frac{2(\sqrt{2}+\sqrt{6})}{8}$ ...taking 2 as a common factor

⇒ $cos(45-60)=\frac{(\sqrt{2}+\sqrt{6})}{4}$

To find the exact values we have to put the values of sq-rt .

As, $\sqrt{2}=1.41$ and $\sqrt{6} =2.44$

Then

⇒ $cos(45-60)=\frac{( 1.41+2.44)}{4}$

⇒ $cos(45-60)=\frac{( 3.85)}{4}$

⇒ $cos(45-60)=0.96$

So the exact value of Cos(45° - 60°) is 0.96 using difference of two angles.

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2 years ago

NO LINKS

torisob [31]

Answer:

(40*4)-(32*4)=32

160-128=32

Step-by-step explanation:

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2 years ago

What is 6÷4? I still do not understand

fgiga [73]

You simply divide 6 by 4 that will get you a answer of 1.5

I hope this help you have a nice day.

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3 years ago

Read 2 more answers

Ella bought some keychains and spent a total of $24 each she can cost the same whole dollar amount. How many she bought between

lesya [120]

Answer:

Step-by-step explanation

Find the factors of 24

1,2,3,4,6,8,12,24

find the number that is in the range of 7 and 11

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2 years ago

Parents wish to have $80,000 available for a child's education. If the child is now 5 years old, how much money must be set asid

Ludmilka [50]

Answer: $27,602.60

Step-by-step explanation:

if the kid is 5 years old, there are 13 years left until he is 18.

Now, suppose that the parents set aside an amount A of money in the account.

As the interest is compounded semiannually is compounded two times per year.

The equation that models this situation is:

M(n) = A*(1 + p/(c*100%))^(c*n)

where:

n is our variable, in this case, years.

p is the percentage, in this case, 6%

n is the number of compounds in one unit of the variable, in this case, we have 2.

A is the initial amount, this is the thing we want to find.

Then our equation will be:

M(n) = A*(1 + 6%/(2*%100))^(2*n)

= A*(1 + 0.03)^(2*n) = A*(1.03)^(2n)

And we want that this is equal to $80,000 when n = 13 (remember that when n = 13, the child will be 18 years old)

M(13) = A*(1.03)^(2*18) = $80,000

A = $80,000/((1.03)^(2*18)) = $27,602.60

Then they should deposit $27,602.60 now to meet their financial goal when the child is 18.

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