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koban [17]
3 years ago
13

Write a system of equations that has no solution.

Mathematics
1 answer:
Helen [10]3 years ago
7 0

Answer:

9x + 4 = 3(3x + 4)

Step-by-step explanation:

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Write the expression in radical form
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Inside the radical it is (96b)^3

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Evaluate the expression when g=8 and h=7. <br> 4g-h
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25 because 4(8)-7 = 32-7 = 25
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What is the diameter of a hemisphere with a volume of 5403 ft", to the nearest tenth<br> of a foot?
lubasha [3.4K]

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Step-by-step explanation:

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3 years ago
Find the equation of the linear function represented by the table below<br> in slope-intercept form.
Arturiano [62]

Answer:

Equation of a line, y = mx+c

Slope (m)= (Y2-Y1)/(X2-X1), let Y2=7, Y1=3 , X2=2 and X1=1

m=(7-3)/(2-1)

= 4/1

= 4

Picking any value of y and its corresponding x including m, put them into the equation of the line

y=mx+c

3 =4(1)+c

3=4+c

3-4=c

-1=c

y=mx+c

y=4x+(-1)

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8 0
3 years ago
Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av
Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using:  distance = speed x time

\implies t=\dfrac{d}{v}

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

\implies t=\dfrac{18}{v}  \ \ \textsf{and} \ \  t=\dfrac{18}{v+15}

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1

Now all we have to do is solve the equation for v:

\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1

\implies \dfrac{18(v+15)+18v}{v(v+15)}=1

\implies 18(v+15)+18v=v(v+15)

\implies 18v+270+18v=v^2+15v

\implies v^2-21v-270=0

\implies (v-30)(v+9)=0

\implies v=30, v=-9

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

8 0
2 years ago
Read 2 more answers
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