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2 years ago

15

Neil and Beth both had soccer practice during the week. Neil practices for 3 hours each week. All together, they practice 4 hour

s each week.

1 answer:

Semenov [28]2 years ago

5 0

1.4166 converted to a fraction

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Which equation is an identity?

spayn [35]

7z + 10 - z = 8z - 2(z - 5)
7z + 10 - z = 8z - 2z + 10
6z + 10 = 6z + 10
6z - 6z = 10 - 10
0 = 0

Therefore, 7z + 10 - z = 8z - 2(z - 5)

3 0

3 years ago

A leprechaun places a magic penny under a girl's pillow. The next night there are 2 magic pennies under her pillow. Each night

11Alexandr11 [23.1K]

Answer:

tn = 2097152 pennies
tn = 20971.52 dollars.

Step-by-step explanation:

A surprisingly large amount of money.

The question is "Does the amount of money just double or do the previous amounts add to the present amount?"

I think it just doubles. Not only that, but she can't spend any of it until night 22 is reached.

tn = a*2^(n - 1)
a = 1 She starts with 1 penny.
n = 22
tn = 1*2^(22 - 1)
tn = 1*2^21
tn = 2097152 pennies
tn = 20971.52 dollars.

8 0

3 years ago

yKpoI14uk [10]

$(-5p^4z^6u)^3$

$= (-5)^3p^{4 \times 3}z^{6 \times 3} u^3$

$= -125p^{12}z^{18} u^3$

---------------------------------------------------------------------------------------------------
$\text {Answer = } -125p^{12}z^{18} u^3 \text { (Answer C) }$
---------------------------------------------------------------------------------------------------

3 0

2 years ago

Read 2 more answers

What are the steps to solving this problem K + 8\5 = 1k

DaniilM [7]

-- Subtract K from each side of the equation.

8/5 = 0

-- There is no value for K that can make this a true statement. So the original equation has no solution.

8 0

3 years ago

If x>2,then x2-x-6/x2-4=

statuscvo [17]

$\frac{x^2-x-6}{x^2-4}=(*)\\------------\\x^2-x-6=0\\a=1;\ b=-1;\ c=-6\\\Delta=b^2-4ac;\ \Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\x_1=\frac{1-\sqrt{25}}{2\cdot1}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x_2=\frac{1+\sqrt{25}}{2\cdot1}=\frac{1+5}{2}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)$
$---------------------\\x^2-4=x^2-2^2=(x-2)(x+2)\\-------------------\\\\(*)=\frac{(x+2)(x-3)}{(x-2)(x+2)}=\frac{x-3}{x-2}$

6 0

3 years ago