Answer:
It would be equal to 15 - (18)
There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.
You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.
-x^6 + 3x^4 + 4x^2
-x^2(x^4 - 3x^2 - 4)
Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.
-x^2(x^4 - 3x^2 - 4)
-x^2(x^2 - 4)(x^2 + 1)
Now we can use the factors of two perfect squares rule to factor the middle parenthesis.
-x^2(x^2 - 4)(x^2 + 1)
-x^2(x - 2)(x + 2)(x^2 + 1)
We would also want to split the term in the front.
-x^2(x - 2)(x + 2)(x^2 + 1)
(x)(-x)(x - 2)(x + 2)(x^2 + 1)
Now we would set each portion equal to 0 and solve.
First root
x = 0 ---> no work needed
Second root
-x = 0 ---> divide by -1
x = 0
Third root
x - 2 = 0
x = 2
Forth root
x + 2 = 0
x = -2
Fifth and Sixth roots
x^2 + 1 = 0
x^2 = -1
x = +/- 
x = +/- i
Answer:
m=21
Step-by-step explanation:
based on the dilation from 'ABC' to 'QRS' (which is 3) m should =21
hope this helps! :)
He has 4 yellow bushes ! :D
The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.
<u>SOLUTION:</u>
Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.
Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.
That is, length of largest side = 3n inches
The other two sides are equally long and are 4 inches longer than the shortest side.
Then, length of remaining two sides = 4 + n inches
We have to find the length of all four sides.
Now, we know that, perimeter = 50 inches

So, length of sides will be,
