Question

Solve for x and y. y=6x+4 y=4x-2

Answer 1

$\left\{\begin{array}{ccc}y=6x+4&(1^o)\\y=4x-2&(2^o)\end{array}\right\\\\\\subtitute\ (1^o)\ to\ (2^o):\\\\6x+4=4x-2\ \ \ \ |subtract\ 4\ from\ both\ sides\\6x=4x-6\ \ \ \ |subtract\ 4x\ from\ both\ sides\\2x=-6\ \ \ \ |divide\ both\ sides\ by\ 2\\\boxed{x=-3}\\\\subtitute\ value\ of\ "x"\ to\ the\ (1^o):\\y=6(-3)+4=-18+4\to \boxed{y=-14}$

$Answer:\boxed{ \left \{ {{x=-3} \atop {y=-14}} \right}$

Answer 2

Since both are already solved for y, we can take each equation and set them equal to each other.

6x+4=4x-2
6x-4x=2x (take 4x away from both sides)
-2-4=-6 (take 4 away from both sides)
2x=-6
-6/2=-3 (divide both sides by 2)
x=-3

we then plug -3 in for an x in one of the equations to get what y is equal to. 
y=6(-3)+4
y=-18+4
y=-14

So, your answers are: y=-14 and x=-3