Answer:
1.the corresponding angles are propositional
2.the corresponding sides are proportional
All angles in triangle inside add up to 180
so
the angles are y, 79,37
therefor
y+79+37=180
solvde for y
y+79+37=180
add
y+116=180
subtract 116 from ot hsides
y=64
angle y=64 degrees
Bah ahaha because i’m trying to get answers to m
Answer:
161.8cm²
Step-by-step explanation:
solve for height which is the opposite
opp=x
sin(theata)= opp./hyp.
sin23=x/30
x=30×sin23
x=11.72cm
height=opposite
height=11.72cm
base=adjacent
base=27.6cm
½of 27.6cm=13.8
13.8cm×11.72cm=161.74 (2d.p)
161.74 rounded to the nearest tenths= 161.7
I'm not sure if it's the answer but it's the closest thing to the options
Answer:
Step-by-step explanation:
ABC have sides: 5, 7 and 10
5^2 + 7^2 = 25+47 = 72 < 10^2
so triangle ABC is obtuse
JKL has sides: 12, 35 and 37
12^2 + 35^2 = 144 + 1225 = 1369 = 37^2
so triangle JKL is right-angled
PQR has sides 12, 10 and 16
12^2 + 10^2 = 144 + 100 = 244 > 16^2
so triangle PQR is acute
