Ask question

Ask question

All categories

3 years ago

7

The specific gravity of a substance is the ratio of its weight to the weight of an equal volume of water. Kerosene weighs 0.82 g

ram per cubic centimeter and water weighs 1 gram per cubic centimeter. What is the specific gravity of kerosene?

2 answers:

netineya [11]3 years ago

8 0

Answer:

The specific gravity of kerosene is 0.82

Step-by-step explanation:

Let

x -----> the weight in grams of a cubic centimeter of Kerosene

y ----> the weight in grams of a cubic centimeter of water

z ---> the specific gravity of a substance

so

$z=\frac{x}{y}$

we have

$x=0.82\ g\\y=1\ g$

substitute the values

$z=\frac{0.82}{1}=0.82$

olga55 [171]3 years ago

7 0

Answer:

0.82

Step-by-step explanation:

The specific gravity of a substance is the ratio of its weight to the weight of an equal volume of water. Kerosene weighs 0.82 gram per cubic centimeter and water weighs 1 gram per cubic centimeter. Therefore, the specific gravity of kerosene is 0.82.

You might be interested in

Show all work to identify the asymptotes and end behavior of the function f(x)= 5x/x-25.

jeyben [28]

Considering the given function and the asymptote concept, we have that:

The vertical asymptote is of x = 25.

The horizontal asymptote is of y = 5.

The end behavior is that as $x \rightarrow \infty, f(x) \rightarrow 5$ .

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity. Hence it also gives the end behavior of the function.

In this problem, the function is:

$f(x) = \frac{5x}{x - 25}$ .

The vertical asymptote is found as follows:

x - 25 = 0 -> x = 25.

The horizontal asymptote is found as follows:

$y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = \lim_{x \rightarrow \infty} 5 = 5$ .

Hence the end behavior is that as $x \rightarrow \infty, f(x) \rightarrow 5$ .

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

3 0

1 year ago

Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.

Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Step-by-step explanation:

GIven that:

$f(x) = 5e^{-x^2} cos (4x)$

The Maclaurin series of cos x can be expressed as :

$\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+... \ \ \ (1)}$

$\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0} \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!} -\dfrac{x^6}{3!}+... \ \ \ (2)}$

From equation(1), substituting x with (4x), Then:

$\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}- \dfrac{(4x)^6}{6!}+...}$

The first three terms of cos (4x) is:

$\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}-...}$

$\mathtt{cos (4x) = 1 - \dfrac{16x^2}{2}+ \dfrac{256x^4}{24}-...}$

$\mathtt{cos (4x) = 1 - 8x^2+ \dfrac{32x^4}{3}-... \ \ \ (3)}$

Multiplying equation (2) with (3); we have :

$\mathtt{ e^{-x^2} cos (4x) = ( 1- x^2 + \dfrac{x^4}{2!} ) \times ( 1 - 8x^2 + \dfrac{32 \ x^4}{3} ) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1+ (-8-1)x^2 + (\dfrac{32}{3} + \dfrac{1}{2}+8)x^4 + ...) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + (\dfrac{64+3+48}{6})x^4+ ...) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Finally , multiplying 5 with $\mathtt{ e^{-x^2} cos (4x) }$ ; we have:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

7 0

3 years ago

Geometry question, need help.

Margaret [11]

It would be choice A

3 0

2 years ago

Mary has $80 and want to purchase $150 Michael Jordan sneakers. How much money she need to have $150?

Lesechka [4]

$70. $150 - $80 = $ 70

3 0

3 years ago

Read 2 more answers

MAKING AN ARGUMENT You and a friend are going hiking but start at different locations. You start at the trailhead and walk 5 mil

lesya [120]

Answer:

$y = 5x$ -- You

$y = 3 + 3x$ --- Your friend

Step-by-step explanation:

Given

You:

Trailhead implies the beginning so:

$Start = 0\ mile$

$Rate = 5miles/hour$

Your Friend

$Start = 3\ mile$

$Rate = 3miles/hour$

Required

Represent as an equation

From the question, we understand that:

$y = distance$

$x = number\ of\ hours$

So, the relationship between $distance\ and\ time\ is:$

$Distance = Start + Rate * Number\ of\ hours$

In terms $of\ x\ and\ y$ , we have:

$y = Start + Rate * x$

For you, the equation becomes:

$y = 0+ 5* x$

$y = 0+ 5x$

$y = 5x$

For your friend, the equation becomes:

$y = 3 + 3 * x$

$y = 3 + 3x$

4 0

2 years ago