Considering the given function and the asymptote concept, we have that:
- The vertical asymptote is of x = 25.
- The horizontal asymptote is of y = 5.
- The end behavior is that as
.
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity. Hence it also gives the end behavior of the function.
In this problem, the function is:
.
The vertical asymptote is found as follows:
x - 25 = 0 -> x = 25.
The horizontal asymptote is found as follows:
.
Hence the end behavior is that as
.
More can be learned about asymptotes at brainly.com/question/16948935
#SPJ1
Answer:
The first three nonzero terms in the Maclaurin series is

Step-by-step explanation:
GIven that:

The Maclaurin series of cos x can be expressed as :


From equation(1), substituting x with (4x), Then:

The first three terms of cos (4x) is:



Multiplying equation (2) with (3); we have :




Finally , multiplying 5 with
; we have:
The first three nonzero terms in the Maclaurin series is

Answer:
-- You
--- Your friend
Step-by-step explanation:
Given
You:
Trailhead implies the beginning so:


Your Friend


Required
Represent as an equation
From the question, we understand that:


So, the relationship between 

In terms
, we have:

For you, the equation becomes:



For your friend, the equation becomes:

