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Anna007 [38]
2 years ago
6

What is the estimated probability that at least two of the puppies will be

Mathematics
2 answers:
goldfiish [28.3K]2 years ago
8 0
Bubble B. 8/10 80%
.....
Allushta [10]2 years ago
8 0
B is the answer!!!!!!!
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Evaluate if m=-6 what is m/2 + m =
love history [14]

Answer:

9

Step-by-step explanation:

they said that m=6 which you can plug in into the problem, now that you know what 'm' is. It will look like this:

6/2 + 6 = ?

6 divided by 2 = 3 so it'll look like this

3 + 6 = 9

7 0
3 years ago
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
Divide and simplify.
balandron [24]
The last one is the correct one.


8 0
3 years ago
Andre and Diego were each trying to solve 2+6=3−8. Describe the first step they each make to the equation.The result of Diego’s
Fiesta28 [93]

Step-by-step explanation:

2+6=3-8

2+6=8

3-8=-5

8=-5

4 0
3 years ago
Olivia is fixing her bicycle. She starts fixing it at 9:34 am and finishes at 1 pm. How much
zysi [14]

Answer:

3 hours 26 minutes

Step-by-step explanation:

26 minutes(9.34am to 10am)+3 hours(10am to 1pm)=3 hours 26 minutes

8 0
2 years ago
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