Let

. Then

. By convention, every non-zero integer

divides 0, so

.
Suppose this relation holds for

, i.e.

. We then hope to show it must also hold for

.
You have

We assumed that

, and it's clear that

because

is a multiple of 3. This means the remainder upon divides

must be 0, and therefore the relation holds for

. This proves the statement.
Step-by-step explanation:
Given the equation:
y = 0.09x where:
- x: represents the cost of the item before tax is added.
- y: represents the amount of sales
=> On a coordinate plane, the x-axis is labeled Cost of Item (in dollars) and the y-axis is labeled sales tax (in dollars)
We create a table of values
x y
0 0
10 0.9
=> the line go through two points (0, 0) and (10, 0.9)
Hence tow dwaw a graph, we just connect two points together.
Please have a look at the attached photo.
Answer:
Step-by-step explanation: