The quadratic formula is -b + or - the square root of b squared - 4 times the a value and c value over 2a. So the roots would be -1.354249 and -6.645751. I believe these are the roots.
Answer:
the answer is -2x^9
Step-by-step explanation:
i know this because of photomath lolll
As we know that the standard equation of circle is
, where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>
Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>
Now , putting values in our standard equation ;
<em>This is the required equation of </em><em>Circle</em>
Refer to the attachment as well !
C) $20
40 divided by 30 is 1.3
1.3 times 15 is 30
There is no restriction upon the domain, the x values, and is all real numbers or (-oo,+oo)
From such it is clear that the domain also contains all real numbers.
The range of f(x) is (-oo,+oo)