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Julli [10]
3 years ago
7

absmiddle" class="latex-formula">
Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
7 0

Answer:

x= 7

x= 4

Step-by-step explanation:

Move terms to the left side

2−11=−28

x^{2}-11x=-28x2−11x=−28

2−11−(−28)=0

Use the sum-product pattern

Identify a, b, and c in your equation and then find two numbers that when multiplied together equal c and when added together equal b.

2−11+28=0

Factor

Write your equation in factored form

(−7)(−4)=0

Create two separate equations

Set each factor equal to zero

−7=0

x-7=0x−7=0

−4=0

Solve

Rearrange and isolate the variable to find each solution

=7

x=7x=7

=4

Solution

=7=4

amid [387]3 years ago
5 0

Answer:

x = 4, 7

Step-by-step explanation:

We start off with the equation x^{2} -11x = -28. from there, we can add 28 to both sides to get x^{2} -11x+28 = 0. From there, we have to factor the equation. In order to factor it, we have to ask ourselves what 2 numbers would add up to -11 and multiply to 28? In this case, the answer would be -7 and -4. So, we get the equation (x-7)(x-4) = 0. Then, we set each part of the equation = 0 to get the anwsers x = 4 and 7. Hope this helps!

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Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

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The range of f(x) is (-oo,+oo)
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