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Kruka [31]
3 years ago
8

What is 8 1/5 - 2? Please show all work.

Mathematics
1 answer:
tiny-mole [99]3 years ago
3 0

Answer:

6 1/5

Step-by-step explanation:

8 1/5-2 = 6 1/5

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Given the following, find the values of all six trig functions of x.
MakcuM [25]

What is csc in the first one?

4 0
3 years ago
Write a system of linear equations for the graph below.​
sp2606 [1]
<h2>Answer:</h2>

We need to determine the equation of both lines first.

  • Line 1: <em>y = -2x + 3</em>
  • Line 2: <em>y = -1/3x - 2</em>

Now that we know the equations, we can set up a system of equations for this graph where both equations are in standard form.

Line 1:

y = -2x + 3\\\\2x + y = 3

Line 2:

y = -\frac{1}{3}x - 2\\\\\frac{1}{3}x + y = -2

<em>Final answer:</em>

2x + y = 3\\\frac{1}{3}x + y = -2

5 0
3 years ago
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What is 9.187 to the nearest tenth? And hundredth and one
Assoli18 [71]
<span> 9.187 to the nearest tenth is 9.2

The 1 in 9.187 is in the tenths place and since the number after it is over 5, you round up. </span>
4 0
3 years ago
Read 2 more answers
I really help with this ill mark u brainliest pls
erma4kov [3.2K]

Answer:

m\angle XYW  = (155 - 20x)\degree

Step-by-step explanation:

m\angle XYZ= m\angle XYW +m\angle WYZ\\\\150\degree = m\angle XYW +(20x-5)\degree \\\\150\degree - (20x-5)\degree = m\angle XYW  \\\\(150 - 20x+5)\degree = m\angle XYW  \\\\(155 - 20x)\degree = m\angle XYW  \\\\m\angle XYW  = (155 - 20x)\degree \\\\

7 0
3 years ago
The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?
Mnenie [13.5K]

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3.  2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

  • mass = 2g
  • molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

133.34g = 6.023*10^2^3

If we equate this

133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

#SPJ1

5 0
2 years ago
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