Answer:
I believe the answer is $17,631.94
Step-by-step explanation:
12000(1.08)∧5=17,631.94
Answer:
The current price of the unit trust = £13,831.72
Step-by-step explanation:
Since it increased 7% per annum in last three years and decreased by 3% per annum before that, it implies that the unit trust decreased by 3% per annum for the first 2 years and then increased by 7% per annum for the next 3 years in the total 5 year period
The invested after 2 years = 12,000*(1-0.03)^2 = £11,290.8
This amount then grows by 7% for the next 3 years making it = 11,290.80*(1+0.07)^3 = £13,831.7155 = £13,831.72 (Rounded to 2 decimals)
The current price of the unit trust = £13,831.72 (Rounded to 2 decimals)
Answer:
Option C (the set of all integers, the set of all rational numbers, and the set of all real numbers).
Step-by-step explanation:
The value of square root of 9 is ±3. This means that there two answers to square root of 9: 3 and -3.
As far as 3 is concerned, it is one of the elements of the natural number set. It is already known that natural numbers are also whole numbers, also integers, also rational numbers, and also real numbers.
As far as -3 is concerned, it is not a natural number since the set of natural numbers does not contain negative numbers. -3 is an integer. Which means that -3 is also a rational number and also a real number.
After identifying the common sets and taking the intersection of both the above classifications, it yields the set of all integers, the set of all rational numbers, and the set of all real numbers, Therefore, Option C is the correct answer!!!
Answer: Taylor is 14 and Jessi is 13
Step-by-step explanation:
Since you can't divide 27 by 2, you would most likely break it in half. SInce the question states that Taylor is still older, she would be 14, and Jessi 13.
Answer:
B)
Step-by-step explanation:
Given f(x) = ( 7 - 8x )²
let f(x) be y,
y = ( 7 - 8x )² .............to find inverse we have to make x the subject.
±√y = 7 - 8x
-8x = √y - 7
x = (±√y - 7 ) / -8
Then,
Inverse of ( 7 - 8x )² is
and is a function.