Answer:
The second graph near the bottom with a Y-intercept of -1
Answer:
Step-by-step explanation:
x² + 4y² = 36
divide by constant
x²/36 + y²/9 = 1
x²/6² + y²/3² = 1
6>3, so length of major axis is 2×6 = 12
I do not completely understand your question, but if you mean area by "murals", then when the width increases, area does, too. For example:
I have a rectangular board that is 5 feet by 3 feet. The area is 15 square feet. I have another board with a longer width, but the same length. It is 5 feet by 4 feet. Its area is 20 square feet.
Answer:
It is an acute triangle.
Step-by-step explanation:
It would be much easier for you to see where I'm getting at if you draw a diagram.
Assume this triangle is labelled ABC where a = 14, b = 21, and c = 16.
cos A = (16^2 + 21^2 - 14^2)/(2(16)(21))
∠A = cos^-1(0.82291...)
∠A ≅ 34.6°
cos B = 16^2 + 14^2 - 21^2)/(2(16)(14))
∠B = cos^-1(0.024...)
∠B ≅ 56.8°
∠C = 180 - (∠A + ∠B)
∠C ≅ 56.8°
Since there is no right-angle nor is there an obtuse angle,
Therefore the triangle is an acute triangle.
Answer: There are 5 grasshoppers, 15 crickets and 20 ladybugs
Step-by-step explanation:
The question in english is:
Jose has found several insects. There are 10 less grasshoppers than crickets. There are 5 less crickets than ladybugs. If Jose has found 5 grasshoppers, how many ladybugs did he find and how many crickets? Write two equations to solve the problem.
Let's tag grasshoppers with
, crickets with
and ladybugs with
.
So, we are tolde there are 10 less grasshoppers than crickets:
(1) We have the first equation
Then, we are told there are 5 less crickets than ladybugs:
(2) This is the second equation
If
and we substitute this in both equations we will have:
(3)
Isolating
:
(4) There are 15 crickets
Substituting (4) in (2):
(5)
Isolating
:
There are 20 ladybugs
Therefore:
There are 15 crickets and 20 ladybugs